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vaieri [72.5K]
3 years ago
10

The interior angles formed by the side of a hexagon have measures of them up to 720° what is the measure of angle a

Mathematics
1 answer:
timofeeve [1]3 years ago
5 0

Answer:

n = 6

Step-by-step explanation:

the formula for interior angle is ( n-2)

but we given the measure of one angle, so solve

720 = (n - 2)180

720/180 = (n - 2)

4 = (n - 2)

combine the like terms

4 + 2 =n

6 = n


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Please help me with this I need this done!!!
mote1985 [20]

Answer:

1=1

2=4

3= <NTR=115

   <RTM=45

  <STN=45

4= A-124

    B-45

    C-45

    D-90

    E-124

5=15

6=?

Step-by-step explanation:

FGHJK

8 0
3 years ago
X / 3 - (x+5) / 5 = 7
Nastasia [14]

Answer:

x= 60

Explanation:

7 0
3 years ago
Convert 28/50to a percent
velikii [3]
The answer is 56%
You first divide 28 by 50=.56, then since it's a decimal, you move the decimal twice to the right to make a percentage=56%
3 0
3 years ago
What is-3/7x-2 in standard form
Eddi Din [679]
If you are given y = (-3/7)x - 2 and you want it in the form Ax+By = C, then...

y = (-3/7)x-2
7*y = 7*( (-3/7)x-2) ... multiply both sides by 7
7y = -3x-14 ... distribute and multiply
7y+3x = -3x-14+3x ... add 3x to both sides
3x+7y = -14

The standard form equation is 3x+7y = -14
3 0
3 years ago
4x^2 y+8xy'+y=x, y(1)= 9, y'(1)=25
jarptica [38.1K]

Answer with explanation:

\rightarrow 4x^2y+8x y'+y=x\\\\\rightarrow 8xy'+y(1+4x^2)=x\\\\\rightarrow y'+y\times\frac{1+4x^2}{8x}=\frac{1}{8}

--------------------------------------------------------Dividing both sides by 8 x

This Integration is of the form ⇒y'+p y=q,which is Linear differential equation.

Integrating Factor

 =e^{\int \frac{1+4x^2}{8x} dx}\\\\e^{\log x^{\frac{1}{8}+\frac{x^2}{2}}\\\\=x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}

Multiplying both sides by Integrating Factor  

x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}\times [y'+y\times\frac{1+4x^2}{8x}]=\frac{1}{8}\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}\\\\ \text{Integrating both sides}\\\\y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=\frac{1}{8}\int {x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}} \, dx \\\\8y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=\int {x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}} \, dx\\\\8y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=-[x^{\frac{9}{8}}]\times\frac{ \Gamma(0.5625, -x^2)}{(-x^2)^{\frac{9}{16}}}\\\\8y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=(-1)^{\frac{-1}{8}}[ \Gamma(0.5625, -x^2)]+C-----(1)

When , x=1, gives , y=9.

Evaluate the value of C and substitute in the equation 1.

6 0
3 years ago
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