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2 years ago

8×4=(A×7)-(A×3)what is the value of A in the equation shown??

Mathematics

1 answer:

Pani-rosa [81]2 years ago

4 0

Answer:

Step-by-step explanation:

8×4 = (A×7) - (A×3) = A(7-3) = A×4

A = 8

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what are the lower, middle and upper quartiles of this data 122, 164, 71, 98, 147, 114, 111, 98, 85, 104, 71, 77

MA_775_DIABLO [31]

71,71,77,85,98,98,104,111,114,122,147,164

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2 years ago

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Which ordered pair is the solution to the system of linear equations y =-7x+2 and y = 9x-14?

shepuryov [24]

Answer:

(1, -5)

Step-by-step explanation:

Solve the system by setting the equations equal to each other, and solving for x:

-7x + 2 = 9x - 14

2 = 16x - 14

16 = 16x

1 = x

So, the x coordinate of the solution will be 1.

Plug in 1 as x into one of the equations, and solve for y

y = -7x + 2

y = -7(1) + 2

y = -7 + 2

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So, the y coordinate is -5.

The ordered pair solution is (1, -5)

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2 years ago

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What is The answer to 1/6x+12=1/2(x-6)

mr Goodwill [35]

Answer:

negative infinite, negative 72

Step-by-step explanation:

i looked it up on google

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2 years ago

You are given g(x)=4x^2 + 2x and

Strike441 [17]

Answer:

324

Step-by-step explanation:

Given:

$g(x)=4x^2+2x\\ \\f(x)=\int\limits^x_0 {g(t)} \, dt$

Find:

$f(6)$

First, find f(x):

$f(x)\\ \\=\int\limits^x_0 {g(t)} \, dt\\ \\=\int\limits^x_0 {(4t^2+2t)} \, dt\\ \\=\left(4\cdot \dfrac{t^3}{3}+2\cdot \dfrac{t^2}{2}\right)\big|\limits^x_0\\ \\=\left(\dfrac{4t^3}{3}+t^2\right)\big|\limits^x_0\\ \\= \left(\dfrac{4x^3}{3}+x^2\right)-\left(\dfrac{4\cdot 0^3}{3}+0^2\right)\\ \\=\dfrac{4x^3}{3}+x^2$