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3 years ago

Solve the equation 2 = -6 – 20x for x. A. -5/2 B. -2/5 C. 2/5 D. 5/2

Mathematics

2 answers:

ludmilkaskok [199]3 years ago

7 0

Hello there! B. -2/5.

To solve for x, you want to get x alone and isolate all other terms.

2 = -6 – 20x - Start by adding 6 to both sides of the equation.

2+6 = -6+6 – 20x ⇒ 8 = -20x

8 = -20x - Next, divide both sides of the equation by -20..

8/-20 = -20/-20x ⇒ -8/20 = x

Now, we have -8/20 as our value for x. The last step is to simplify. Since 8 and 20 are both divisible by 4, divide both sides of the fraction by 4.

x = -2/5. This is your final answer. I hope this helps and have a great day! ~ saturns

Edit: Sorry for the typos, i fixed them! You have to press suuuper hard to get the S key on my keyboard to work :)

prohojiy [21]3 years ago

3 0

Answer: - 2/5

Step-by-step explanation: Isolate the vcariable by divding each side by factors that don't contain the variable.

Exact Form: x = - 2/5

Deciaml form: x = -0.4

Hope this helps! :) ~Zane

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Read 2 more answers

In a geometric sequence, a4 = 54 and a7 = 1,458. what is the 12th term? <br><br> answer: B) 354,294

slamgirl [31]

Option B:

The 12th term is 354294.

Solution:

Given data:

$a_4=54$ and $a_7=1458$

To find $a_{12}:$

The given sequence is a geometric sequence.

The general term of the geometric sequence is $a_n=a_1\ r^{n-1}$ .

If we have 2 terms of a geometric sequence $a_n$ and $a_k$ (n > K),

then we can write the general term as $a_n=a_k\ r^{n-k}$ .

Here we have $a_4=54$ and $a_7=1458$ .

So, n = 7 and k = 4 ( 7 > 4)

$a_7=a_4\ .\ r^{7-4}$

$1458=54\ . \ r^3$

This can be written as

$$r^3=\frac{1458}{54}$

$$r^3=27$

$$r^3=3^3$

Taking cube root on both sides of the equation, we get

r = 3

$a_{12}=a_7\ .\ r^{12-7}$

$=1458\ .\ r^5$

$=1458\ .\ 3^5$

$a_{12}=354294$

Hence the 12th term of the geometric sequence is 354294.

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2 years ago