It’s the second one. -4(3-8x)
Answer:
Step-by-step explanation:
First and foremost, all quadratics have a domain of all real numbers (as long as we are not given only a portion of the graph, or one with endpoints. Our graph does not have endpoints, so it is assumed that the tails will continue to go down into negative infinity and at the same time, the x coordinates will keep growing as well.) Since our quadratic is upside down, it has a max. That means that none of the values on the graph will be above that point. All the values will be below that highest point (the highest y-value). Y-values indicate range, and since our highest y-value is at y = 2, then the range is
y ≤ 2
Answer:
The equation of the line in the slope-intercept form is y = -5x + 79
Step-by-step explanation:
The slope-intercept form of the linear equation is y = m x + b, where
- m is the slope of the line
- b is the y-intercept
∵ The slope of the line is -5
∴ m = -5
∵ The form of the equation is y = m x + b
→ Substitute the values of m in the form of the equation
∴ y = -5x + b
→ To find b substitute x and y in the equation by the coordinates
of any point on the line
∵ The line passes through the point (18, -11)
∴ x = 18 and y = -11
∵ -11 = -5(18) + b
∴ -11 = -90 + b
→ Add 90 to both sides to find b
∵ -11 + 90 = -90 + 90 + b
∴ 79 = b
→ Substitute it in the equation
∴ y = -5x + 79
∴ The equation of the line in the slope-intercept form is y = -5x + 79
Answer:-9+2I
Step-by-step explanation: MUTIPLYING THE SECOND BRACKET BY THE NEGATIVE SIGN.
(-3-3I)(-6+5I)
COLLECTING LIKE TERMS
(-3-6)(-3I+5I)
=-9+2I
