Four consecutive integers... n, n+1, n+2, n+3.
The product of the 1st and 4th is four less than twice the 1st multiplied by the 4th.
n(n+3)=2n(n+3)-4 perform indicated multiplications...
n^2+3n=2n^2+6n-4 subtract n^2 from both sides
3n=n^2+6n-4 subtract 3n from both sides
n^2+3n-4=0 factor
n^2-n+4n-4=0
n(n-1)+4(n-1)=0
(n+4)(n-1)=0, and since n>0
n=1
So the four numbers are 1, 2, 3, 4
check...
1(4)=2(1)4-4
4=8-4
4=4
Answer:
ewqvrdvfgbt2nbvcx
Step-by-step explanation:
Answer:
All Real Numbers
Step-by-step explanation:
........
<span>We have to calculate the average speed if we know the distance and time that Johnatan can jog. The distanece: d = 3 2/5 miles = 3.4 miles. t = 7/8 hour = 0.875 h. Then we will use the formula for the average speed ( velocity ): v = d / t. v = 3.4 m / 0.875 h = 3.866 mph. Answer: The average speed is 3.866 mph.</span>