Johnathon can jog 3 2/5 miles in 7/8 hour. Find his average speed in miles per hour

1 answer:

8 0

<span>We have to calculate the average speed if we know the distance and time that Johnatan can jog. The distanece: d = 3 2/5 miles = 3.4 miles. t = 7/8 hour = 0.875 h. Then we will use the formula for the average speed ( velocity ): v = d / t. v = 3.4 m / 0.875 h = 3.866 mph. Answer: The average speed is 3.866 mph.</span>

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ycow [4]

Answer:

Step-by-step explanation:

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3 years ago

A process is producing a particular part where the thickness of the part is following a normal distribution with a µ = 50 mm and

Hitman42 [59]

Answer:

0.13% probability that this selected sample has an average thickness greater than 53

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

In this problem, we have that:

$\mu = 50, \sigma = 5, n = 25, s = \frac{5}{\sqrt{25}} = 1$

What is the probability that this selected sample has an average thickness greater than 53?

This is 1 subtracted by the pvalue of Z when X = 53. So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{53 - 50}{1}$

$Z = 3$

$Z = 3$ has a pvalue of 0.9987

1 - 0.9987 = 0.0013

0.13% probability that this selected sample has an average thickness greater than 53

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3 years ago

Simplify the following : x^2y^-3 / x^5y^2

Likurg_2 [28]

Answer:

Step-by-step explanation:

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