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Zolol [24]
3 years ago
12

a quadrilateral has vertices A(11,-7), B(9,-4), C(11,-1), and D(13,4). Quadrilateral ABCD is a . If the vertix C(11,-1) were shi

fted to the point C(11,1), quadrilateral ABCD would be a .
Mathematics
2 answers:
Maurinko [17]3 years ago
7 0

Answer:

A quadrilateral formed by the vertices A(11,-7), B(9,-4), C(11,-1), and D(13,4) forms a rhombus

If the vertex C(11,-1) were shifted to the point C'(11,1), quadrilateral ABC'D would be a kite

Step-by-step explanation:

A quadrilateral formed by the vertices A(11,-7), B(9,-4), C(11,-1), and D(13,4) forms a rhombus. A rhombus is a quadrilateral whose all sides have equal length means it has four equal sides.

If the vertex C(11,-1) were shifted to the point C'(11,1), quadrilateral ABC'D would be a kite because a kite has two pairs of equal sides. A kite is a quadrilateral whose four sides can be grouped into two pairs of equal-length sides which are adjacent to each other....

postnew [5]3 years ago
5 0

Answer:

a. rhombus b. kite

Step-by-step explanation:

plato

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nirvana33 [79]

Hello macelynn190!

\huge \boxed{\mathfrak{Question} \downarrow}

\huge \tt \frac{5 - 2(a + 3b)}{2}

\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}

To solve this question we need to substitute the given values of 'a' & 'b' in the equation & then simplify it.

Given,

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Now, substitute this in the place of 'a' & 'b'..

\large \tt \frac{5 - 2(a + 3b)}{2}  \\  =  \large   \underline{\underline{\tt \:  \frac{5 - 2((4) + 3(1))}{2} }}

Lastly, simplify it...

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Hope it'll help you!

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