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2 years ago

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True or False: In a uniform probability distribution, any random variable is just as likely as any other random variable to occu

r, provided the random variables belong to the distribution.'

1 answer:

agasfer [191]2 years ago

3 0

Answer:

True

Step-by-step explanation:

trust me, i remember this question

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Please help big hug for whoever does

timurjin [86]

Answer:

SAS POSTULATE can prove the triangle congruent

Step-by-step explanation:

plz mark me brainlist

5 0

2 years ago

Mary has $135 to spend on clothes. She wants to purchase winter boots for $70 and some sweaters that cost $20 each. Write an ine

creativ13 [48]

Answer:

1 pair of boots and 6 sweaters

Step-by-step explanation:

70+20s = 135

-70 -70

20s = 135

divide 20 both sides

s = 6.75

She can buy 6 sweaters because she cannot buy half a sweater.

s - sweaters

I need brainliest please

5 0

2 years ago

Read 2 more answers

Please Subtract the Following Fractions.

vovangra [49]

¡Hola!

Your answer to the question is 10/12.

Step-by-step explanation:

By using the y^2-y^1/x^2-x^1

12-2= 10

16-4= 12

So your answer is 10/12.

Hope this Helps!

4 0

2 years ago

If y-3x=9, 7x+y=25, what is the value of x and y?

lianna [129]

$\bold{\rm{Given}}\text{ : If y - 3x = 9, 7x + y = 25, what is the value of x and y}?$

$\bold{\rm{Solution}} \text{: We'll solve this by substitution method}$

$\dashrightarrow y - 3x = 9 \\ \\ \dashrightarrow \boxed{y = 9 + 3x } \qquad .. \sf eq(1)$

$\text{we got the value of y now getting the value of x}$

$\looparrowright 7x + y = 25 \\ \\ \looparrowright 7x = 25 - y \\ \\ \looparrowright \boxed{x = \frac{25 - y}{7}} \qquad .. \sf eq(2)$

$\text{Now, putting y = 9 + 3x in eq(2)}$

$\hookrightarrow x = \frac{25 - y}{7} \\ \\ \hookrightarrow x = \frac{25 - 9 + 3x}{7} \\ \\ \hookrightarrow 7x = 25 - 9 + 3x \\ \\ \hookrightarrow 7x - 3x = 16 \\ \\ \hookrightarrow 4x = 16 \\ \\ \hookrightarrow x = \frac{16}{4} \\ \\ \star \quad \boxed{ \green{ \frak{ x = 4}}}$

$\text{Now we know the value of x, for getting y we need to put x in eq(1)}$

$: \implies y = 9 + 3x \\ \\ : \implies y = 9 + 3(4) \\ \\ : \implies y = 9 + 12 \\ \\ \star \quad \boxed{\frak{ \green{y = 21}}}$

$\text{Hence, values of x and y are} \: \frak{ \green{4}} \: \text{and} \: \frak{ \green{21}} \: \text{respectively}.$

4 0

1 year ago

If (42)^p = 41^4, what is the value of p?

babymother [125]

First you need to make both bases the same:

Lets remove the ^p and ^4

To make the base of 42 equal to 41, you would have 41^x = 41

X - ln(42) / ln(41) = 1.00648904

Now you have 41^1.00648904(p) = 41^4

Now the bases are equal so we need to set the exponents to equal:

1.00648904(p) = 4

Divide both sides by 1.00648904 to solve for P

P = 4 / 1.00648904

P = 3.97421114

4 0

3 years ago