Question

Im giving 30 points pls help

Answer 1

Step-by-step explanation:

Pathagory and Theorem

a^2+b^2=c^2

(x-3)^2+(x-4)^2=6^2

expand:

2x^2-14x+25=36

2x^2-14x-11=0

x=(\sqrt{71}+7)/2

perimeter=(x-3)+(x-4)+6=2x-1

insert the value for x into 2x-1

$\sqrt{71}$+6=perimeter

Hope that helps :)

Answer 2

9514 1404 393

Answer:

  2x -1

Step-by-step explanation:

The perimeter is the sum of the side lengths.

  P = 6 + (x -4) + (x -3)

  P = 2x -1 . . . . . . collect terms

The perimeter is 2x -1.

_____

Additional comment

There is nothing in the problem statement that suggests this is a right triangle. Without knowing at least one angle, we cannot solve for a numerical value for the perimeter. The problem title suggests we're to leave the result in polynomial form.