Im giving 30 points pls help
2 answers:
Step-by-step explanation:
Pathagory and Theorem
a^2+b^2=c^2
(x-3)^2+(x-4)^2=6^2
expand:
2x^2-14x+25=36
2x^2-14x-11=0
x=(\sqrt{71}+7)/2
perimeter=(x-3)+(x-4)+6=2x-1
insert the value for x into 2x-1
Hope that helps :)
9514 1404 393
Answer:
2x -1
Step-by-step explanation:
The perimeter is the sum of the side lengths.
P = 6 + (x -4) + (x -3)
P = 2x -1 . . . . . . collect terms
The perimeter is 2x -1 .
_____
<em>Additional comment</em>
There is nothing in the problem statement that suggests this is a right triangle. Without knowing at least one angle, we cannot solve for a numerical value for the perimeter. The problem title suggests we're to leave the result in polynomial form.
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I mean, it depends what type of math you're doing but I can try!
Answer:
a=8 b=6
Step-by-step explanation:
Using the Pythagorean theorem, a^2+b^2=c^2, and in this case, a^2+b^2=10^2 = 100
so a^2+b^2=100
8^2+6^2=100
64+36=100 ✔
and since A is longer than B, a=8, b=6
If you are trying to solve for x, then
Answer:
. i think it's wrong
45 - 15 - 15 = 45 - 30
