I NEED THE ANSWER NOWWWWWWWWWWWWWW

The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e

I am Lyosha [343]

Answer:

(a) The proportion of tenth graders reading at or below the eighth grade level is 0.1673.

(b) The 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.198, 0.260).

Step-by-step explanation:

Let X = number of students who read above the eighth grade level.

(a)

A sample of n = 269 students are selected. Of these 269 students, X = 224 students who can read above the eighth grade level.

Compute the proportion of students who can read above the eighth grade level as follows:

$\hat p=\frac{X}{n}=\frac{224}{269}=0.8327$

The proportion of students who can read above the eighth grade level is 0.8327.

Compute the proportion of tenth graders reading at or below the eighth grade level as follows:

$1-\hat p=1-0.8327$

$=0.1673$

Thus, the proportion of tenth graders reading at or below the eighth grade level is 0.1673.

(b)

the information provided is:

n = 709

X = 546

Compute the sample proportion of tenth graders reading at or below the eighth grade level as follows:

$\hat q=1-\hat p$

$=1-\frac{X}{n}$

$=1-\frac{546}{709}$

$=0.2299\\\approx 0.229$

The critical value of z for 95% confidence interval is:

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

Compute the 95% confidence interval for the population proportion as follows:

$CI=\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

$=0.229\pm 1.96\times \sqrt{\frac{0.229(1-0.229)}{709}}\\=0.229\pm 0.03136\\=(0.19764, 0.26036)\\\approx (0.198, 0.260)$

Thus, the 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.198, 0.260).

5 0

3 years ago

What is the difference of the rational expressions below?

Rom4ik [11]

Answer:

** +2x

Step-by-step explanation:

All the other ones can be it any thing will have difference but how can you do it?

* -sign mutipulcation

2x+* can be different.

O c, OA is N X+2 and more is not a equation. * - can be times really any number.

3 0

3 years ago

An FM radio station signal travels in a 40-mile radius. An AM radio station

MrMuchimi

Answer:

4976.28 square miles (nearest hundredth)

Step-by-step explanation:

$\textsf{Area of a circle}=\pi r^2 \quad \textsf{(where r is the radius)}$

FM radio station

Given:

r = 40 miles

$\implies \textsf{Area}=\pi (40)^2=1600 \pi \: \sf miles^2$

AM radio station

Given:

r = 4 miles

$\implies \textsf{Area}=\pi (4)^2=16 \pi \: \sf miles^2$

Difference:

$\begin{aligned}\implies \textsf{FM area - AM area} & =1600 \pi - 16 \pi\\ &= 1584 \pi\\ & =4976.23\:\textsf{square miles (nearest hundredth)}\end{aligned}$

3 0

2 years ago

Y+3=7(x-2) in standard form

uysha [10]

7x- y = 17 is the standard form

4 0

3 years ago

Find the equation of the line that passes through (1,2) and is perpendicular to

uysha [10]

Answer:

Remember that the slope of perpendicular lines are negative reciprocals of each other.

Step-by-step explanation:

y = 1 - 2x the slope is -2 the value of the x term.

So the slope of the new line using point (- 1, 2) is 1/2.

Now use y = mx + b where y = -1, x = 2, and m = 1/2 .

y = mx + b

-1 = 1/2(2) + b solve for "b", the y-intersect

-1 = 1 + b

-2 = b

The line that is perpendicular to y = 1 - 2x is y = 1/2x - 2

3 0

2 years ago