If ~v = hv1, v2, v3i and ~w = hw1, w2, w3i are vectors and c is a scalar, then
(a) c~v = hcv1, cv2, cv3i
(b) ~v + ~w = hv1 + w1, v2 + w2, v3 + w3i
(c) ~v − ~w = hv1 − w1, v2 − w2, v3 − w3i.
There were 160 athletes at the meet.
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$5000 I think should be right
Answer is A
Once you add 29 to negative 34 you will get negative 5 and then divide 5 and you will end up with negative 1 always flip the sign when dealing with a negative