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MaRussiya [10]
3 years ago
12

Which of the following hypotheses cannot be tested using the scientific method

Chemistry
2 answers:
Arturiano [62]3 years ago
7 0
I believe it's answer #3. Logically, at least.

You can test #1 through trial and error.
You can experiment #2 also through trial and error.
You cannot test #3 through trial and error, because that would be catastrophic.
You can test #4 through a survey and individual study and data collection.
Mashcka [7]3 years ago
5 0

Answer: The bombing of Hiroshima ended World War II is correct.

Explanation:

Using the scientific method, we can check :

1) If the temperature is increased, the reaction rate of HCl and NaOH will increase.

2) Cold weather causes car tires to deflate.

3) If students do more homework their grades will improve.

All the above can done by carefully observing the data.

But the The bombing of Hiroshima ended World War II cannot be tested by scientific method.

Because it is based on pre determined outcome but scientific method is not.

Hence, The bombing of Hiroshima ended World War II is correct.

You might be interested in
How many molecules are in 68.0 g of H2S
Kryger [21]

The correct answer is 12.044 × 10²³ molecules.  

The molecular mass of H₂S is 34 gram per mole.  

Number of moles is determined by using the formula,  

Number of moles = mass/molecular mass

Given mass is 68 grams, so no of moles will be,  

68/34 = 2 moles

1 mole comprises 6.022 × 10²³ molecules, therefore, 2 moles will comprise = 6.022 × 10²³ × 2

= 12.044 × 10²³ molecules.  


3 0
3 years ago
Hurricanes derive their energy from: Group of answer choices the latent heat of condensation. the latent heat of fusion. the lat
klemol [59]

Hurricanes derive their energy from the Latent heat of condensation.

Hence, Option (1) is correct answer.

<h3>What is Latent Heat ? </h3>

The heat that is released or absorbed during a phase change of a substance is known as Latent heat.

<h3>What is Hurricanes ?</h3>

Hurricanes is basically a type of storm called a tropical cyclone. These are intense low pressure areas. Hurricanes derive their energy from the latent heat of CONDENSATION.

Thus from the above conclusion we can say that Hurricanes derive their energy from the Latent heat of condensation.

Hence, Option (1) is correct answer.

Learn more about the Latent heat here: brainly.com/question/5401454

#SPJ4  

7 0
2 years ago
A mixture of 75 mole% methane and 25 mole% hydrogen is burned with 25% excess air. Fractional conversions of 90% of the methane
son4ous [18]

Solution :

Consider a mixture of methane and hydrogen.

Take the basis as 100 moles of the mixture.

The mixture contains 75% of methane and 25% of hydrogen by mole and it is burned with 25% in excess air.

Moles of methane = 0.75 x 100

Moles of hydrogen = 0.25 x 100

The chemical reactions involved during the reaction are :

$CH_4+2O_2 \rightarrow CO_2 + 2H_2O$

$CH_4+1.5O_2 \rightarrow CO+2H_2O$

$H_2+0.5O_2 \rightarrow H_2O$

The fractional conversion of methane is 90%

Number of moles of methane burned during the reaction is = 0.9 x 75

                                                                                                   = 67.5

Moles of methane leaving = initial moles of methane - moles of methane burned

                                           = 75 - 67.5

                                           = 7.5 moles

Fractional conversion of hydrogen is 85%

The number of moles of hydrogen burned during the reaction is = 0.85 x 25

                                                                                                   = 21.25

Moles of hydrogen leaving = initial moles of hydrogen - moles of hydrogen burned

                                           = 25 - 21.25

                                           = 3.75 moles

Methane undergoing complete combustion is 95%.

$CO_2$ formed is = 0.95 x 67.5

                       = 64.125 moles

$CO$ formed is = 0.05 x 67.5

                       = 3.375 moles

Oxygen required for the reaction is as follows :

From reaction 1, 1 mole of the methane requires 2 moles of oxygen for the complete combustion.

Hence, oxygen required is = 2 x 75

                                            = 150 moles

From reaction 3, 1 mole of the hydrogen requires 0.5 moles of oxygen for the complete combustion.

Hence, oxygen required is = 0.5 x 25

                                            = 12.5 moles

Therefore, total oxygen is = 150 + 12.5 = 162.5 moles

Air is 25% excess.

SO, total oxygen supply = 162.5 x 1.25 = 203.125 moles

Amount of nitrogen = $203.125 \times \frac{0.79}{0.21} $

                                = 764.136 moles

Total oxygen consumed = oxygen consumed in reaction 1 + oxygen consumed in reaction 2 + oxygen consumed in reaction 3

Oxygen consumed in reaction 1 :

1 mole of methane requires 2 moles of oxygen for complete combustion

 = 2 x 64.125

 = 128.25 moles

1 mole of methane requires 1.5 moles of oxygen for partial combustion

= 1.5 x 3.375

= 5.0625 moles

From reaction 3, 1 mole of hydrogen requires 0.5 moles of oxygen

= 0.5 x 21.25

= 10.625 moles.

Total oxygen consumed = 128.25 + 5.0625 + 10.625

                                        = 143.9375 moles

Total amount of steam = amount of steam in reaction 1 + amount of steam in reaction 2 + amount of steam in reaction 3

Amount of steam in reaction 1 = 2 x 64.125 = 128.25 moles

Amount of steam in reaction 2 = 2 x 3.375 = 6.75 moles

Amount of steam in reaction 3  = 21.25 moles

Total amount of steam = 128.25 + 6.75 + 21.25

                                     = 156.25 moles

The composition of stack gases are as follows :

Number of moles of carbon dioxide = 64.125 moles

Number of moles of carbon dioxide = 3.375 moles

Number of moles of methane = 7.5 moles

Number of moles of steam = 156.25 moles

Number of moles of nitrogen = 764.136 moles

Number of moles of unused oxygen = 59.1875 moles

Number of moles of unused hydrogen = 3.75 moles

Total number of moles of stack  gas

= 64.125+3.375+7.5+156.25+764.136+59.1875+3.75

= 1058.32 moles

Concentration of carbon monoxide in the stack gases is

$=\frac{3.375}{1058.32} \times 10^6$

= 3189 ppm

b).  The amount of carbon monoxide in the stack gas can be decreased by increasing the amount of the excess air. As the amount of the excess air increases, the amount of the unused oxygen and nitrogen in the stack gases will increase and the concentration of CO will decrease in the stack gas.  

6 0
3 years ago
Cual es el disolvente de acero
drek231 [11]

Answer:

I do not know what is the solvent for steel is. sorry

Explanation:

5 0
3 years ago
Characteristic of meteor​
Sati [7]

Explanation:

Many meteorites have iron or nickel in them, so they are heavier (and denser) than Earth rocks. Some meteorites have pits (regmaglypts) on the outside, which look like deep thumbprints. Meteorites are not bubbly, and do not have holes. Meteorite are usually not round.

8 0
2 years ago
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