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3 years ago

Which of the following hypotheses cannot be tested using the scientific method

2 answers:

7 0

I believe it's answer #3. Logically, at least.

You can test #1 through trial and error.
You can experiment #2 also through trial and error.
You cannot test #3 through trial and error, because that would be catastrophic.
You can test #4 through a survey and individual study and data collection.

Mashcka [7]3 years ago

5 0

Answer: The bombing of Hiroshima ended World War II is correct.

Explanation:

Using the scientific method, we can check :

1) If the temperature is increased, the reaction rate of HCl and NaOH will increase.

2) Cold weather causes car tires to deflate.

3) If students do more homework their grades will improve.

All the above can done by carefully observing the data.

But the The bombing of Hiroshima ended World War II cannot be tested by scientific method.

Because it is based on pre determined outcome but scientific method is not.

Hence, The bombing of Hiroshima ended World War II is correct.

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How many valenence electons does sodium have?

olganol [36]

8 valence electrons :)

7 0

3 years ago

Read 2 more answers

How many grams of acetylene are produced by adding water to 5.00 g CaC2?

Murljashka [212]

Answer:

2.03125g of acetylene

Explanation:

First thing's first, we have to write out the balanced chemical equation;

CaC2(s) + 2H2O(l) → Ca(OH)2(aq) + C2H2(g)

Water is in excess, so CAC2 is our limiting reactant. i.e it determines the amount of product that would be formed.

1 mol of CaC2 produces 1 mol of C2H2

In terms of mass;

Mass = Number of moles * Molar mass

where the molar mass of the elements are;

Ca = 40g/mol

C = 12g/mol

H = 1g/mol

CaC2 = 40+ (2*12) = 64g/mol

C2H2 =( 2 * 12) + ( 2 * 1) = 26g/mol

64g (1 * 64g/mol) of CaC2 produces 26g ( 1mol * 26g/mol) of C2H2

5g would produce x?

64 = 26

5 = x

Upon solving for x we have;

x = (5 * 26) / 64

x = 2.03125g

5 0

3 years ago

Fynjy0 [20]

Answer:

larva hatching, larva with legs, young newt, adult newt, in that order

4 0

2 years ago

Find the fugacity coefficient of a gaseous species of mole fraction 0.4 and fugacity 25 psia in a mixture at a total pressure of

Oksana_A [137]

<u>Answer:</u> The fugacity coefficient of a gaseous species is 1.25

<u>Explanation:</u>

Fugacity coefficient is defined as the ratio of fugacity and the partial pressure of the gas. It is expressed as $\bar{\phi}$

Mathematically,

$\bar{\phi}_i=\frac{\bar{f_i}}{p_i}$

Partial pressure of the gas is expressed as:

$p_i=\chi_iP$

Putting this expression is above equation, we get:

$\bar{\phi}_i=\frac{\bar{f_i}}{\chi_iP}$

where,

$\bar{\phi}_i$ = fugacity coefficient of the gas

$\bar{f_i}$ = fugacity of the gas = 25 psia

$\chi_i$ = mole fraction of the gas = 0.4

P = total pressure = 50 psia

Putting values in above equation, we get:

$\bar{\phi}_i=\frac{25}{0.4\times 50}\\\\\bar{\phi}_i=1.25$

Hence, the fugacity coefficient of a gaseous species is 1.25

8 0

3 years ago

Which of the following statements is not an accurate description of a factor that contributes to the ordering of the spectrochem

MArishka [77]

Answer:

Higher oxidation state metals form stronger bong with ligands

Explanation:

Ligand strength are based on oxidation number, group and its properties

5 0

3 years ago