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algol13
2 years ago
9

Round the mmHg readings to the nearest whole number. Round the kPa readings to the nearest tenth. Round the atm readings to the

nearest hundredth. Convert a pressure of 1.76 atm to _____ torr.
Chemistry
1 answer:
Eva8 [605]2 years ago
6 0

i love jesus and i love my mommy

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Air is an example of a mixture because the elements and compounds that make up air retain their individual properties.
inysia [295]

Answer:

True

Explanation:

True definition of a mixture itself

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3 years ago
A student uses a dye to change the colour of his tee-shirt. he fills a metal bucket with water. When the bucket is heated, what
Tanya [424]

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The particles begin to vibrate faster and more.

Explanation:

Adding heat to matter increases the energy, thus creating more movement. Eventually, the bucket will melt, turning to a liquid. While it is a sold, it still has particle movement, just not enough to break volume or shape.

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3 years ago
Please help!!! I will mark Brainliest !!!!
shepuryov [24]

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c

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5 0
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It is desired to produce 2.25 grams of dichloromethane (CH2Cl2) by the following reaction. If the percent yield of dichlorometha
Allushta [10]

Answer:- 3.12 g carbon tetrachloride are needed.

Solution:- The balanced equation is:

CH_4+CCl_4\rightarrow 2CH_2Cl_2

From given actual yield and percent yield we will calculate the theoretical yield that would be further used to calculate the grams of carbon tetrachloride.

percent yield formula is:

percent yield = (\frac{actual}{theoretical})100

65.5=(\frac{2.25}{theoretical})100

theoretical=(\frac{2.25(100)}{65.5})

theoretical = 3.44 g

From balanced equation, there is 2:1 mol ratio between dichloethane and carbon tetrachloride.

Molar mass of dichloroethane is 84.93 gram per mol and molar mass of carbon tetrachloride is 153.82 gram per mol.

3.44gCH_2Cl_2(\frac{1molCH_2Cl_2}{84.93gCH_2Cl_2})(\frac{1molCCl_4}{2molCH_2Cl_2})(\frac{153.82gCCl_4}{1molCCl_4})

= 3.12gCCl_4

So, 3.12 grams of carbon tetrachloride are needed to be reacted.

8 0
3 years ago
What is the acceleration of a 50 kg object pushed with a force of 500 newtons?
son4ous [18]

Answer:

F = MA

500 = 50 multiply by A

A= 500/50

A= 10m/s2

3 0
3 years ago
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