1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
mihalych1998 [28]
3 years ago
13

Sulfuric acid (h2so4) is spilled on a laboratory bench. which chemical would be useful for neutralizing the acid

Chemistry
1 answer:
marysya [2.9K]3 years ago
8 0
Sulphuric acid (H2SO2) is a dibasic acid. It generated H+ ions when dissolved in water. In order to neutralize an acid, a base containing hydroxy ion (OH-) will be required. 

NaOH, Ca(OH)2, KOH, etc. can be used to neutralize H2SO4.

If NaOH is used as a base, following reaction is initiated.

2NaOH     +      H2SO4      →     Na2SO4     +     H2O     
 (base)                (acid)                  (salt)
You might be interested in
Which of the following substances is an element? A. carbon (C) B. water (H2O) C. methane (CH4) D. brass (Cu + Zn)
Sladkaya [172]
The Answer is Carbon.
8 0
2 years ago
Read 2 more answers
2. Which one is the modal class?
Sonja [21]

Answer:

a.3-5 is the modal class.

7 0
3 years ago
True or False
Grace [21]
The answer to this is true.
6 0
3 years ago
At a particular temperature a 2.00-L flask at equilibrium contains 2.80 ✕ 10-4 mol N2, 2.50 ✕ 10-5 mol O2, and 2.00 ✕ 10-2 mol N
zhenek [66]

Answer : The value of equilibrium constant (K) is, 5.71\times 10^4

Explanation :

First we have to calculate the concentration of N_2,O_2\text{ and }N_2O

\text{Concentration of }N_2=\frac{\text{Moles of }N_2}{\text{Volume of solution}}=\frac{2.80\times 10^{-4}mol}{2.00L}=1.4\times 10^{-4}M

and,

\text{Concentration of }O_2=\frac{\text{Moles of }O_2}{\text{Volume of solution}}=\frac{2.50\times 10^{-5}mol}{2.00L}=1.25\times 10^{-5}M

and,

\text{Concentration of }N_2O=\frac{\text{Moles of }N_2O}{\text{Volume of solution}}=\frac{2.00\times 10^{-2}mol}{2.00L}=1.00\times 10^{-2}M

Now we have to calculate the value of equilibrium constant (K).

The given chemical reaction is:

N_2(g)+O_2(g)\rightarrow 2N_2O(g)

The expression for equilibrium constant is:

K=\frac{[N_2O]^2}{[N_2][O_2]}

Now put all the given values in this expression, we get:

K=\frac{(1.00\times 10^{-2})^2}{(1.4\times 10^{-4})\times (1.25\times 10^{-5})}

K=5.71\times 10^4

Thus, the value of equilibrium constant (K) is, 5.71\times 10^4

7 0
3 years ago
In a chromatography experiment, chlorophyll pigments are separated using paper. What is the stationary phase in this experiment?
stira [4]
The correct answer is paper

7 0
2 years ago
Other questions:
  • What is the term for a substance that acts on proton donor in one reaction and as a proton acceptor in another?
    12·1 answer
  • What is the molarity of 2 moles of iron oxide,FeO in 8 Liters of water
    9·1 answer
  • What is it called when liquid changes state to a gas?
    8·1 answer
  • HELP PLEASE?! I will upvote all answers!
    11·1 answer
  • Express 0.5 mg/mL in ug/uL
    9·1 answer
  • Which of the following is a synthesis reaction?
    11·1 answer
  • Consider the molecule SiCl4. The electronegativity values for Si and Cl are 1.8 and 3.0, respectively. Based on these values and
    6·2 answers
  • which would you think would be a stronger interaction and why: an interaction between a sodium ion and the prtial negative charg
    6·1 answer
  • Structural formula of 1 methyl butane​
    7·1 answer
  • Write the full electron configuration for a Ca+ ion.​
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!