All categories

3 years ago

Sulfuric acid (h2so4) is spilled on a laboratory bench. which chemical would be useful for neutralizing the acid

1 answer:

8 0

Sulphuric acid (H2SO2) is a dibasic acid. It generated H+ ions when dissolved in water. In order to neutralize an acid, a base containing hydroxy ion (OH-) will be required.

NaOH, Ca(OH)2, KOH, etc. can be used to neutralize H2SO4.

If NaOH is used as a base, following reaction is initiated.

2NaOH + H2SO4 → Na2SO4 + H2O
(base) (acid) (salt)

You might be interested in

One success of Johann Döbereiner's law of triads was that it organized most of the known elements into three-element groups base

jenyasd209 [6]

That statement is true

it was easy to organize 'all' the elements in a group of threes because back then they only knew about 15 - 20 elements

hope this helps

4 0

3 years ago

Read 2 more answers

If the equilibrium constant of the reaction is 0.85, then which statement is true if the mass of A is 10.5 grams; the density of

snow_tiger [21]

Answer:

E. Q < K and reaction shifts right

Explanation:

Step 1: Write the balanced equation

A(s) + 3 B(l) ⇄ 2(aq) + D(aq)

Step 2: Calculate the reaction quotient (Q)

The reaction quotient, as the equilibrium constant (K), only includes aqueous and gaseous species.

Q = [C]² × [D]

Q = 0.64² × 0.38

Q = 0.15

Step 3: Compare Q with K and determine in which direction will shift the reaction

Since Q < K, the reaction will shift to the right to attain the equilibrium.

8 0

2 years ago

Calculate the mass in grams, in 2.28 mol of H2SO4. Please show your work to receive credit.

solmaris [256]

Answer:

98g

Explanation:

h=1*2=2

s=32

0=16*4=64

64+32+2=98

4 0

2 years ago

Which factor below does not affect how fast a solute dissolves in a solvent?

Anit [1.1K]

Stirring this is because the three elements are factors affecting dissolving of a solvent. Eg temprature affects in hotness or coldness, Particle size affects whether it is big or small while quantity of soluble affects by the amount

3 0

2 years ago

Read 2 more answers

What is the MOLAR heat of combustion of methane(CH₄) if 64.00g of methane are burned to heat 75.0 ml of water from 25.00°C to 95

melamori03 [73]

Answer:

-5.51 kJ/mol

Explanation:

Step 1: Calculate the heat required to heat the water.

We use the following expression.

$Q = c \times m \times \Delta T$

where,

c: specific heat capacity
m: mass
ΔT: change in the temperature

The average density of water is 1 g/mL, so 75.0 mL ≅ 75.0 g.

$Q = 4.184J/g.\°C \times 75.0g \times (95.00\°C - 25.00\°C) = 2.20 \times 10^{3} J = 2.20 kJ$

Step 2: Calculate the heat released by the methane

According to the law of conservation of energy, the sum of the heat released by the combustion of methane (Qc) and the heat absorbed by the water (Qw) is zero

Qc + Qw = 0

Qc = -Qw = -22.0 kJ

Step 3: Calculate the molar heat of combustion of methane.

The molar mass of methane is 16.04 g/mol. We use this data to find the molar heat of combustion of methane, considering that 22.0 kJ are released by the combustion of 64.00 g of methane.

$\frac{-22.0kJ}{64.00g} \times \frac{16.04g}{mol} = -5.51 kJ/mol$

8 0

2 years ago