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Lunna [17]
2 years ago
14

Which particle diagram represents a mixture of three substances

Chemistry
1 answer:
Anni [7]2 years ago
4 0

Following the key in the diagram (see the attached image), the only particle diagram that represents a mixture of three substances is diagram 2.

To simplify it, let us replace the key in the diagram as follows;

  1. atom of one element = A
  2. atom of different element = B

Diagram 1 consists of only AA and AB

Diagram 2 consists of AA, BB, and AB.

Diagram 3 consists of AA and ABA

Diagram 4 consists of AA and BAB

Thus, only diagram 2 has a mixture of 3 substances.

More on mixtures can be found here: brainly.com/question/6594631

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How many objects are in a mole of objects?
lakkis [162]
Your Question: {How many objects are in a mole?}

Helpful Knowledge: (We Know the amount in an object: 12g or C^12)

{A number of objects that are in a mole of objects?}

Well for the question it is pretty easy to answer because a number of objects in One mole would equal 6.02 × 10²³ 

Which 6.02 × 10²³ is an Avogadro's Number. 

So it depends on how many objects you have.

So for every object you have, One mole would equal 6.02 × 10²³. Or 62,000,000,000,000,0000,000,000. Big Number am I right. So that's why we just use 6.02 × 10²³.

Anywho, your answer would be 6.02 x 10²³ x n. 
N would equal the number of objects you're calculating. 

Final Answer: 6.02 x 10²³ x (n) = (Your Answer)

Hope this helps! Have a great day. If you need anything else, feel free to hope right in my inbox. Or comment below. ↓

6 0
3 years ago
Вычислить равновесные концентрации частиц в растворе, содержащем 0,01 моль/л Cu(NO3)2 и 1,0 моль/л NH3.
Wewaii [24]

Answer:

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3 0
2 years ago
How are the graphs of the sine function and the cosine function different?
Zielflug [23.3K]
They are different by a phase shift of pi/2
3 0
3 years ago
What dissolved solid has the highest concentration in the ocean? sodium chloride
jeyben [28]

Answer:

chloride and sodium.

Explanation:

These two make up over 90% of all dissolved ions in seawater.

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3 0
2 years ago
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4.45 kcal of heat was added to increase the temperature of a sample of water from 23.0 °C to 57.8 °C. Calculate
Alona [7]

Answer:

m = 4450 g

Explanation:

Given data:

Amount of heat added = 4.45 Kcal ( 4.45 kcal ×1000 cal/ 1kcal = 4450 cal)

Initial temperature = 23.0°C

Final temperature = 57.8°C

Specific heat capacity of water = 1 cal/g.°C

Mass of water in gram = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 57.8°C - 23.0°C

ΔT = 34.8°C

4450 cal = m × 1 cal/g.°C × 34.8°C

m = 4450 cal / 1 cal/g

m = 4450 g

4 0
3 years ago
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