Choose from the following descriptions of solid:

Calcum chloride contains only calcum and chloride What is the fomula for this compound? fou need the Peodie Table for thia quest

mafiozo [28]

Answer:

$CaCl_2$

Explanation:

Calcium is the element of the group 2 and period 4 which means that the valence electronic configuration is $[Ar]4s^2$ .

Chlorine is the element of the group 17 and period 3 which means that the valence electronic configuration is $[Ne]3s^23p^5$ .

Thus, calcium losses 2 electrons to 2 atoms of chlorine and these 2 atoms of chlorine accepts each electron to form ionic bond. This is done in order that the octet of the atoms are complete and they become stable.

Ca Cl

2 1

Cross multiplying the valency, We get, $CaCl_2$

Thus, the formula of calcium chloride is $CaCl_2$ .

3 0

3 years ago

How is a compound different from a mixture?

Marrrta [24]

Answer: a compound is a chemically made or chemically bonded where as a mixture is just something added like a smoothie

6 0

2 years ago

Read 2 more answers

A hiker climbs a hill. How does the potential energy of the hiker change as she climbs higher?

zloy xaker [14]

The answer should be A

6 0

3 years ago

What is the simplest aromatic compound? toluene benzene cyclohexane cyclopropane

pav-90 [236]

It’s Benzene, I do believe :) hope this helped, good luck!

3 0

3 years ago

When metallic aluminum is added to a solution containing iron(II) sulfate a reaction occurs. What species is being oxidized in t

REY [17]

Answer: Aluminium is getting oxidized in the given chemical reaction.

Explanation:

Oxidation reaction is defined as the chemical reaction in which an atom looses its electrons. The oxidation number of the atom gets increased during this reaction.

$X\rightarrow X^{n+}+ne^-$

Reduction reaction is defined as the chemical reaction in which an atom gains electrons. The oxidation number of the atom gets reduced during this reaction.

$X^{n+}+ne^-\rightarrow X$

For the given chemical reaction:

$2Al(s)+3FeSO_4(aq.)\rightarrow Al_2(SO_4)_3(aq.)+3Fe(s)$

The half cell reactions for the above reaction follows:

Oxidation half reaction: $Al\rightarrow Al^{3+}+3e^-$

Reduction half reaction: $Fe^{2+}+2e^-\rightarrow Fe$

As, aluminium is loosing 3 electrons to form aluminium cation. Thus, it is getting oxidized. Iron is gaining 2 electrons to form iron anion. Thus, it is getting reduced.

Hence, the oxidized species of the given reaction is aluminium.

4 0

3 years ago