3x - y = 6 and y = x - 4, use addition to solve the linear system of equations.

1 answer:

6 0

3x-y=6
y=x-4
solve by substitution
3x-x+4=6
2x=2
x=1

Now that you know x, but in in the equation to find y (either equation will work)
y= 1-4
y= -3

now that you have both answers, let's check them.

3(-1) - (-3) =6
yes, it works....

Hopefully this makes sense!

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$a_n = \frac{n^3 - n}{n^2 + 5n}\\\\ \lim_{n \to \infty} a_n = \lim_{n \to \infty} \frac{n^3 - n}{n^2 + 5n}$

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