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Nadusha1986 [10]
4 years ago
8

3x - y = 6 and y = x - 4, use addition to solve the linear system of equations.

Mathematics
1 answer:
Aleonysh [2.5K]4 years ago
6 0
3x-y=6
y=x-4
solve by substitution
3x-x+4=6
2x=2
x=1

Now that you know x, but in in the equation to find y (either equation will work)
y= 1-4
y= -3

now that you have both answers, let's check them.

3(-1) - (-3) =6
yes, it works....

Hopefully this makes sense!
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You return from a trip with 480 Canadian dollars. How much are your Canadian dollars worth in U.S. dollars? Use the exchange rat
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591 Dollars 42 Cents (591 Dollars when rounded)

6 0
3 years ago
a triangle has an area of 54 m2 and a height of 9m how long is the base of the triangle entered your answer in the box
Delvig [45]
Answer:
base of the triangle = 12 m

Explanation:
Area of the triangle = 1/2 * base * height
We are given that:
area = 54 m^2
height = 9 m

Substitute in the equation to get the base as follows:
Area of the triangle = 1/2 * base * height
54 = 1/2 * base * 9
108 = 9*base
base = 12 m

Hope this helps :)
7 0
3 years ago
Read 2 more answers
List the ordered pairs in the equivalence relations produced by these partitions of {a, b, c, d, e, f, g}: a) {a,b},{c,d},{e,f,g
finlep [7]

Answer:

a)  {a,b} , {c,d} , {e,f,g},{a , b } = {(a,a) (b,b) (a,b) (b,a)},{c , d } = {(c,c) (d,d) (c,d) (d , c) } ,{e,f,g} = {(e,e) (e,f)  (f,e) (e,g) (f,f) (f,g) ( g,e) (g,f)(g,g)}  

b) { (a,a)(b,b)(c,c)(c,d)(d,c)(d,d)(e,e)(e,f)(f,e)(f,f)(g,g)

c)  {(a,a)(a,b)(b,b)(b,a)(a,c)(c,a)(b,c)(c,b)(c,c)(d,a)(a,d)(b,d)(d,b)(d,c)(c,d)(d,d)(c,c)(c,f)(f,c)(f,f)(c,g)(g,c)(f,g)(g,f)(g,g)

Step-by-step explanation:

a) {a,b} , {c,d} , {e,f,g}

  {a , b } = {(a,a) (b,b) (a,b) (b,a)}

  {c , d } = {(c,c) (d,d) (c,d) (d , c) }

  {e,f,g} = {(e,e) (e,f)  (f,e)  (e,g) (f,f) (f,g) ( g,e) (g,f) (g,g)}  

b) {a} ,{b},{c,d} ,{e,f},{g}

     { (a,a)(b,b)(c,c)(c,d)(d,c)(d,d)(e,e)(e,f)(f,e)(f,f)(g,g)}

c)  {a,b,c,d},{e,f,g}

   {(a,a)(a,b)(b,b)(b,a)(a,c)(c,a)(b,c)(c,b)(c,c)(d,a)(a,d)(b,d)(d,b)(d,c)(c,d)(d,d)(c,c)(c,f)(f,c)(f,f)(c,g)(g,c)(f,g)(g,f)(g,g)

4 0
3 years ago
Isotope mass (amu) abundance (%) 1 203.97304 1.390 2 205.97447 24.11 3 206.97590 22.09 4 207.97665 52.41 find the atomic mass of
Nata [24]
Answer:
average atomic mass = 207.2172085 amu

Explanation:
To get the average atomic mass of an element using the abundance of its isotopes, all you have to do is multiply each isotope by its percentage of abundance and then sum up all the products.

For the question, we have:
203.97304 amu has an abundance of <span>1.390% (0.0139)
</span>205.97447 amu has an abundance of 24.11% (0.2411)
206.97590 amu has an abundance of 22.09% (0.2209)
207.97665 amu has an abundance of 52.41 % (0.5241)

The average atomic mass can be calculated as follows:
average atomic mass = 203.97304(0.0139) + 205.97447(0.2411)
                                     + 206.97590(0.2209) + 207.97665(0.5241)
average atomic mass = 207.2172085 amu

Hope this helps :)
7 0
4 years ago
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