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Maru [420]
2 years ago
8

I have no idea what I'm doing :^

Mathematics
2 answers:
Dovator [93]2 years ago
7 0
C+s+a=800
a=.5(s+c)
2.5c+4s+5.5a=3450
mars1129 [50]2 years ago
5 0

Answer:

press this link and u will get the answers

https://www.math.tamu.edu/~rosanna/141/WIR2_done.pdf

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Barb and John each have a savings account with a sum of money in it. Barb and John each begin to add a set amount of money each
BigorU [14]

Answer:

The answers are, "John saves $35 dollars the first week" and "John is saving at a faster rate than Barb"


8 0
3 years ago
Read 2 more answers
Consider the dot plot which shows the distribution of data collected on the number of pets at home. Which statement BEST describ
ioda
C) The mean Value is closer to the middle of the range than the Median

Hope this helped!
3 0
2 years ago
Read 2 more answers
NEED HELP.
kirza4 [7]

Answer:

For instance, if the point (1, 3) is on the graph of the function, then the point (3, 1) is on the graph of the inverse. That is, if you start with x = 1, you will go to y = 3; then you plug this into the inverse, and you'll go right back to x = 1, where you started from.

5 0
2 years ago
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Write an equation that represents a vertical translation 7 units down of the graph of g(x) = 21.
xenn [34]

Answer:

<h2>h(x) = 14</h2>

Step-by-step explanation:

f(x) + n - translation n units up

f(x) - n - translation n units down

f(x + n) - translation n units to the left

f(x - n) - translation n units to the right

===========================================

g(x) = 21

translation 7 units down: g(x) - 7 = 21 - 7 = 14

3 0
3 years ago
Which real numbers are zeros of the function?
monitta
<h3><u>The roots are -1/2, 0, 2, and 3.</u></h3>

Let's trying factoring this polynomial.

We can factor an x out of each term to start.

x(2x^3 - 9x^2 + 7x + 6)

We now know one of the roots is going to be zero.

Using the rational roots theorem, and the remainder theorem, we can try to find some more roots that way.

Factors of 6: 1, 2, 3, 6.

Factors of 2: 1

Possible rational roots: +/-1/2, +/-1, +/-2, +/-3/2, +/-3, +/-6

Using the remainder theorem, we can plug these values into the polynomial, and if we get a remainder of zero, we know it's a root.

-1/2(2(-1/2)^3 - 9(-1/2)^2 + 7(-1/2) + 6) = 0

Our first root is -1/2.

We can successfully factor a -1/2 out of this polynomial.

After diving the polynomial by -1/2, we're left with: 2x^2 - 10x + 12.

We can now try using the AC method to get our last two roots.

First, we can factor this polynomial to simplify it.

Divide all terms by 2.

2(x^2 - 5x + 6)

Now let's try using the AC method.

The digits -3 and -2 satisfy the criteria.

2(x - 3)(x - 2)

We now have all of our roots: 0, -1/2, 2, and 3.


6 0
3 years ago
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