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Maru [420]
3 years ago
8

I have no idea what I'm doing :^

Mathematics
2 answers:
Dovator [93]3 years ago
7 0
C+s+a=800
a=.5(s+c)
2.5c+4s+5.5a=3450
mars1129 [50]3 years ago
5 0

Answer:

press this link and u will get the answers

https://www.math.tamu.edu/~rosanna/141/WIR2_done.pdf

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The fraction bar represents which equation?
Vera_Pavlovna [14]

Answer:

what equation silly

Step-by-step explanation:

3 0
3 years ago
Which ordered pairs are solutions to the inequality y−4x≥−5
Crank
You have to do substitution in both sides e) (-4,2)
3 0
3 years ago
Algebraically solve the systems of equations by using f(x)=g(x). <br> f(x)=x^2-6x+10<br> g(x)=x^2-2
Kaylis [27]

Answer:

x=2

Step-by-step explanation:

3 0
4 years ago
Can anyone please help me solve this one?<br>the result have to be in positive integers​
GalinKa [24]

Step-by-step explanation:

(a²-b²)(c²-d²) = a²c² - a²d² - b²c² + b²d²

(b²-d²)(c²-a²) = b²c² - a²b² - c²d² + a²d²

the sum of both is

a²c² + b²d² - a²b² - c²d² = a²(c²-b²) + d²(b²-c²) =

= a²(c²-b²) - d²(c²-b²) = (c²-b²)(a²-d²) = 2021

after a little check we find 2021 is only divisible by 43 and 47 (or 1 and 2021).

so, it is clear that our expression resembles

43×47 = 2021

that means that e.g. c²-b² = 43, and a²-d² = 47

or the other way around, it does not matter.

what squared integer numbers give a difference of 43 ? and 47 ?

squared numbers

1 4 9 16 25 36 49 64 81 100 121 144 169 196 225 256

289 324 361 400 441 484 529 576

aha ! 484 - 441 = 43

and 576 - 529 = 47

so, we get

a = sqrt(576) = 24

b = sqrt(441) = 21

c = sqrt(484) = 22

d = sqrt(529) = 23

one could also use the formula for consecutive squared numbers

(n+1)² = n² + 2n + 1

under the assumption that the 2 numbers are convective (which it turns out they are in this example) we get

(n+1)² - n² = 2n + 1 = 43

2n = 42

n = 21

n+1 = 22

and for 47

2n + 1 = 47

2n = 46

n = 23

n+1 = 24

4 0
3 years ago
The probability of winning on an arcade game is 0. 659. if you play the arcade game 30 times, what is the probability of winning
mrs_skeptik [129]

The probability of winning exactly 21 times is:-0.32

Given,

The probability of winning on an arcade game, p = 0.659

Number of times you play arcade game, n = 30

By assuming this as a normal distribution, we get

Mean=μ=30×0.659 =19.77

Standard deviation, σ = \sqrt{np(1-p)}

= \sqrt{30(0.659)(1-0.659)}

≈ 2.60

Let X be a binomial variable

Then, the z score for x = 21 will be:

z = (x - μ) / σ = \frac{21-19.77}{2.60}

≈ 0.47

Now, the probability of winning exactly 21 times

P (x ≥ z) = P (21 ≥ 0.47) = 0.32

Hence the probability of winning exactly 21 times is 0.32

Learn more about probability here:-brainly.com/question/13067945

#SPJ4

                         

5 0
2 years ago
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