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Len [333]
3 years ago
6

What can you say about flat bicycle tire

Mathematics
2 answers:
aalyn [17]3 years ago
6 0

Answer:

Preventing a tire from puncturing is undoubtedly the best way.

Step-by-step explanation:

Sure to puncture the bicycle tire is very annoying, it can happen if you go over a nail, glass or some sharp object. Some procedures can prevent this from happening, a good tip is to avoid the corners, and be careful whenever the tire is wet, you can also use different tires according to the terrain you are riding, there are also several inner tubes that you can use. can change depending on the terrain.

Also, never forget about Calibration and maintain proper air volume.

Finally, there are also anti-puncture tapes that can be very useful for times of emergency.

Elis [28]3 years ago
5 0
The bicycle tire is flat
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vivado [14]

Answer:

student a answered correctly

Step-by-step explanation:

student b didn't multiply the crossproducts

6 0
3 years ago
Read 2 more answers
1. If <1 is 120 degrees , what is the measure of <2?
natali 33 [55]

Answer:

240

Step-by-step explanation:

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3 years ago
At sally's diner, combo meals come with either chips or fries. of the 115 customers on Friday 80% ordered combo means. of these
34kurt

3/4 = 0.8

115 x 0.8 = 92

Final Answer:

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4 0
3 years ago
In △ABC, m∠A=39°, a=11, and b=13. Find c to the nearest tenth.
Talja [164]

For this problem, we are going to use the <em>law of sines</em>, which states:

\dfrac{\sin{A}}{a} = \dfrac{\sin{B}}{b} = \dfrac{\sin{C}}{c}


In this case, we have an angle and two sides, and we are trying to look for the third side. First, we have to find the angle which corresponds with the second side, B. Then, we can find the third side. Using the law of sines, we can find:

\dfrac{\sin{39^{\circ}}}{11} = \dfrac{\sin{B}}{13}


We can use this to solve for B:

13 \cdot \dfrac{\sin{39^{\circ}}}{11} = \sin{B}

B = \sin^{-1}{\Big(13 \cdot \dfrac{\sin{39^{\circ}}}{11}\Big)} \approx 48.1


Now, we can find C:

C = 180^{\circ} - 48.1^{\circ} - 39^{\circ} = 92.9^{\circ}


Using this, we can find c:

\dfrac{\sin{39^{\circ}}}{11} = \dfrac{\sin{92.9^{\circ}}}{c}

c = \dfrac{11\sin{92.9^{\circ}}}{\sin{39^{\circ}}} \approx \boxed{17.5}


c is approximately 17.5.

8 0
3 years ago
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nikitadnepr [17]

Answer:

Your answer is right! It's (-2, 8)

8 0
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