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solong [7]
3 years ago
15

What is the smallest number of parts that a rectangle could be divided into compare fractions of 5/8 and 3/4

Mathematics
1 answer:
Mashutka [201]3 years ago
3 0
You would have to multiply the top and bottom of both fractions, to get equal number between them,
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If x+1/x = 5 find the value of x^3 +1/x^3. pls solve​
Korolek [52]

Answer:

1) solve x+1/x = 5

\frac{x + 1}{x}  = 5

x + 1 = 5x

x - 5x =  - 1

- 4x =  - 1

x =  \frac{ -1}{ - 4}

x =  \frac{1}{4}

2) solve x³+1/x³

x {}^{3}  +  \frac{1}{x {}^{3} }

substitute x = 1/4 into the expression

( \frac{1}{4} ) {}^{3}  +  \frac{1}{( \frac{1}{4}) {}^{3}  }

\frac{1}{64}  +  \frac{1}{ \frac{1}{64} }

\frac{1}{64}  +  \frac{64 \times 1}{1}

\frac{1}{64}   + 64

\frac{4097}{64}  \: or \: 64.02

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3 years ago
What is the range of this set of test scores?<br>{76, 82, 54. 100, 100, 82. 100. 93. 100.93}​
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84 add the dives by all the numbers
4 0
3 years ago
Read 2 more answers
Can someone please help me?
CaHeK987 [17]

Answer:

there just adding 2 more stars ,, 1 has 2 , 2 has 4, and 3 has 6

Step-by-step explanation:

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3 years ago
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Step-by-step explanation:

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3 years ago
The mean cost of a five pound bag of shrimp is 40 dollars with a standard deviation of 7 dollars. If a sample of 51 bags of shri
eimsori [14]

Answer:

P(|\bar{x}-40| > 0.6)=0.5404

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 40 dollars

Standard Deviation, σ = 7 dollars

Sample size,n = 51

We are given that the distribution of cost of shrimp is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

Standard error due to sampling =

=\dfrac{\sigma}{\sqrt{n}} = \dfrac{7}{\sqrt{51}} = 0.9801

P(sample mean would differ by true mean by more than 0.6)

P(|\bar{x}-40| > 0.6)\\\Rightarrow = 1-P(39.4

P(39.4 \leq x \leq 40.6) \\\\= P(\displaystyle\frac{39.4 - 40}{0.9801} \leq z \leq \displaystyle\frac{40.6-40}{0.9801})\\\\ = P(-0.6121 \leq z \leq 0.6121)\\= P(z \leq 0.6121) - P(z < -0.6121)\\= 0.7298 - 0.2702 =0.4596

P(|\bar{x}|-40 > 0.6)\\= 1-0.4596=0.5404

0.5404 is the required probability.

4 0
3 years ago
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