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3 years ago

What is the smallest number of parts that a rectangle could be divided into compare fractions of 5/8 and 3/4

Mathematics

1 answer:

Mashutka [201]3 years ago

3 0

You would have to multiply the top and bottom of both fractions, to get equal number between them,

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Calculate the area of each shape below. Figures are not drawn to scale.

STatiana [176]

Answer:

The area of the triangle is 168 meters

Step-by-step explanation:

Formula to find the area of a triangle:

Area = 1/2 Base x Height

So, first you need to identify the base and the height. The base is 16m + 8m, and the height is 14m. All you have to do is plug in the numbers:

Area = 1/2 (16 + 8) x 14

Then, you solve:

Area = 1/2 (16 + 8) x 14

Area = 1/2 24 x 14

Area = 1/2 336

Area = 168 meters

So, the area of the triangle is 168 meters

6 0

3 years ago

FIND THE VOLUME ILL GIVE BRAINLIEST

mrs_skeptik [129]

1454.13 ( the 3 is infinite) mm^3

Step-by-step explanation:

1/3 × 13.3 × 16 × 20.5 = 1454.13 ( the 3 is infinite, I don't know how to put a line over a number on here)

I hope this helps, have a good day!

5 0

3 years ago

Jayden and Sheridan both tried to find the missing side of the right triangle. A right triangle is shown. One leg is labeled as

stellarik [79]

Answer:

Sheridan's Work is correct

Step-by-step explanation:

we know that

The lengths side of a right triangle must satisfy the Pythagoras Theorem

$c^{2}=a^{2}+b^{2}$

where

a and b are the legs

c is the hypotenuse (the greater side)

In this problem

Let

$a=7\ cm\\c=13\ cm$

substitute

$13^{2}=7^{2}+b^{2}$

Solve for b

$169=49+b^{2}$

$b^{2}=169-49$

$b^{2}=120$

$b=\sqrt{120}\ cm$

$b=10.95\ cm$

we have that

Jayden's Work

$a^{2}+b^{2}=c^{2}$

$a=7\ cm\\b=13\ cm$

substitute and solve for c

$7^{2}+13^{2}=c^{2}$

$49+169=c^{2}$

$218=c^{2}$

$c=\sqrt{218}\ cm$

$c=14.76\ cm$

Jayden's Work is incorrect, because the missing side is not the hypotenuse of the right triangle

Sheridan's Work

$a^{2}+b^{2}=c^{2}$

$a=7\ cm\\c=13\ cm$

substitute

$7^{2}+b^{2}=13^{2}$

Solve for b

$49+b^{2}=169$

$b^{2}=169-49$

$b^{2}=120$

$b=\sqrt{120}\ cm$

$b=10.95\ cm$

therefore

Sheridan's Work is correct

6 0

3 years ago

Read 2 more answers

Points

valentinak56 [21]

I think A... I might be wrong

8 0

3 years ago

Find the measure of the missing angles in the triangle below round your answer to the nearest degree

navik [9.2K]

Answer:

a. 40°

b. 21°

Step-by-step explanation:

a. Reference angle = θ

Opposite = 5

Adjacent = 6

Apply TOA:

$Tan (\theta) = \frac{Opp}{Adj}$

$Tan (\theta) = \frac{5}{6}$

$\theta = Tan^{-1}(\frac{5}{6})$

$\theta = 40$ (nearest degree)

b. Reference angle = x

Opposite = 5

Hypotenuse = 14

Apply SOH:

$Sin (x) = \frac{Opp}{Hyp}$

$Sin (x) = \frac{5}{14}$

$x = Sin^{-1}(\frac{5}{14})$

$x = 21$ (nearest degree)

3 0

3 years ago