Question

Can anyone help mee!!! A set of data has a normal distribution with a mean of 52 and a standard deviation of 8. Find the percent of data within the following interval.
less than 52
%
The percent of data within the given interval is
(Type an integer or a decimal)

Answer 1

Answer:

P (X > 52) = 0.5

Step-by-step explanation:

Standard Deviation = SD,

Mean = M

Since the Mean is 52 and the Standard Deviation is 8 we have:

P (X<52) = P (X - M < 52 - 52) = P (X - M/SD < 52 - 52/8)

Since X - M / SD = Z and 52 - 52/8 = 0 we have:

P (X < 52) = P (Z < 0)

Use the Standard Normal Distribution Table to find that:

P (X < 0) = 0.5