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3 years ago

Can someone help me with b

Mathematics

1 answer:

larisa86 [58]3 years ago

8 0

Answer:

A) is actually 10 1/3 B) is 5 14/15

Step-by-step explanation:

Please Mark Brainliest if i get the correct answer. 100% sure the answer is right . adn i use a calculator soup

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Select all the factors of: 7x2 − 28 options: 7 7x (x + 2) (x − 2) (x2 + 4)

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Answer:

7(x-2)(x+2)

Step-by-step explanation:

7x^2 -28

Factor out a 7

7(x^2 -4)

The terms inside the parentheses is the difference of squares, so it is factorable (a^2-b^2) = (a-b)(a+b)

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3 years ago

Show that √(1-cos A/1+cos A) =cosec A - cot A

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Hi there!

$\sqrt{\frac{1-cosA}{1+cosA}} =$

We can begin by multiplying by its conjugate:

$\sqrt{\frac{1-cosA}{1+cosA}} * \sqrt{\frac{1+cosA}{1+cosA}} = \\\\\sqrt{\frac{(1-cosA)(1 + cosA)}{(1+cosA)(1 + cosA)}} =$

Simplify using the identity:

$1 - cos^2A = sin^2A$

$\sqrt{\frac{(1-cos^2A)}{(1+cosA)^2}} =\\\\\sqrt{\frac{(sin^2A)}{(1+cosA)^2}} =$

Take the square root of the expression:

${\frac{sinA}{1+cosA} =$

Multiply again by the conjugate to get a SINGLE term in the denominator:

${\frac{sinA}{1+cosA} * {\frac{1-cosA}{1-cosA} =\\$

Simplify:

${\frac{sinA(1-cosA)}{1-cos^2A} =$

Use the above trig identity one more:

${\frac{sinA(1-cosA)}{sin^2A} =$

Cancel out sinA:

${\frac{(1-cosA)}{sinA} =$

Split the fraction into two:

${\frac{1}{sinA} - \frac{cosA}{sinA} =$

Recall:

$1/sinA = cscA\\\\cosA/sinA = cotA$

Simplify:

$\frac{1}{sinA} + \frac{cosA}{sinA} = \boxed{cscA - cotA}$

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