Answer:
The correct answer will be- 200
Explanation:
The cell cycle in eukaryotes mostly takes place in four phases: G₁, S, G₂ and M phase in sequence.
The DNA replication takes place during S phase which doubles the amount of DNA in a cell after which during M- phase the DNA divides into the daughter cell.
The amount of DNA present during G₂ phase is the 200 pg which will remain same until anaphase I as the segregation of chromosomes to the daughter cells takes place in the anaphase. Therefore, the amount of DNA observed after G₂ phase will remain 200 pg till metaphase I.
Thus, 200 is the correct answer.
Answer:
The bone has broken and either severed or blocked the blood vessels
Explanation:
The only consumables that is not digested and is immediately absorbed, would be water, it is nothing but a polar compound that does not yield as much energy as all of the other molecules.
We can’t see the picture :(
Maybe post another question but with the picture
Answer:
Thymidine dimers is likely to be repair as soon as it is originated but if left unrepaired then it causes frame shift mutations.
Explanation:
In case of Bacterium if UV irradiation induces covalent linkage of two thymidine present adjacently to each other or on a single strand to make thymidine dimers.
These either excised via DNA repair enzyme like Endonuclease V and the proof reading activity of DNA polymerase I enzyme help in incorporation of nucleotide by taking the unmutated original strand as a template.
These dimers if not excised before second round of replication than the sequence of newly synthesized strand will be altered. As DNA polymerase III enzyme read thymidine dimers as single thymidine nucleotide and incorporate only 1 adenine in the newly synthesizing complementary strand which results in frame shift mutations
It is the mutation in which reading frame of codons is shifted or altered due to deletion or addition of a single nucleotide.
