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4 years ago

Does anyone know the answer?

Mathematics

1 answer:

Mice21 [21]4 years ago

4 0

Answer: 32

Step-by-step explanation:

This is a geometric sequence.

I've attached the solution.

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PLEASE HELP im dying over here

Iteru [2.4K]

$\dfrac{x}{24\sqrt{2}}=\cos45^\circ\\\\\\\dfrac{x}{24\sqrt{2}}=\dfrac{\sqrt{2}}{2}\qquad\qquad\qquad\text{(cross multiply)}\\\\\\2x=24\sqrt{2}\cdot\sqrt{2}\\\\2x=24\cdot2\quad|:2\\\\\boxed{x=24}$

7 0

3 years ago

Is (-3,2)(−3,2)left parenthesis, minus, 3, comma, 2, right parenthesis a solution of -4x -10y < -9−4x−10y<−9minus, 4, x, m

r-ruslan [8.4K]

Answer:

The answer to your question is The point (-3, 2) is not a solution

Step-by-step explanation:

Inequality

- 4x - 10y < - 9

-point (-3, 2)

Process

1.- To solve this problem, just substitute the point in the inequality and simplify

a) Substitution

-4(-3) - 10(2) < - 9

b) Simplification

12 - 20 < - 9

c) Result

- 8 < - 9

This is false, -8 > -9

7 0

3 years ago

In the figure, m and n are rays.

suter [353]

Is there a picture to go along with this??

4 0

4 years ago

Write a definite integral that represents the area of the region. (Do not evaluate the integral.)

joja [24]

Answer:

$\int_{-1}^{1}7(x^{3}-x)\:dx$

Step-by-step explanation:

1) The other curve is $y=0$ then the common points of both curves are x-intercepts, the roots of $y=7(x^{3}-x)$

$y=7(x^{3}-x)\Rightarrow 7(x^3-x)=0 \Rightarrow 7(x^{3}-x)=7x(x-1)(x-1)\Rightarrow \\S=\left ( 0,0 \right ),\left ( -1,0 \right ),\left ( 1,0 \right )$

2). Then those intersection points are the upper and the lower limits. Plugging in to this formula for they belong to the interval [-1,1]:

$\int_{a}^{b}|f(x)-g(x)dx$

$\int_{a}^{b}|f(x)-g(x)dx \Rightarrow \int_{-1}^{1}|7(x^{3}-x)-0|dx \Rightarrow \int_{-1}^{1}7(x^{3}-x)\:dx$

8 0

3 years ago

Round 915 to the nearest ten

mixas84 [53]

The answer would be 920. hope that helped

6 0

3 years ago