I found my notes for this exact paper and I have that first problem written. hopefully this helps
Answer:
The given equation cannot be written in slope intercept form
Step-by-step explanation:
we know that
Is the equation of the line in slope intercept form
where
m is the slope
b is the y-intercept
In this problem we have
This is a vertical line (parallel to the y-axis)
The slope is undefined
therefore
The given equation cannot be written in slope intercept form
Answer:
Divide 2 by 6
Step-by-step explanation:
Answer:
cos²x
Step-by-step explanation:
(a-b)(a+b)=a²-b²
sin²x+cos²x=1 => cos²x=1-sin²x
(1 − sin x)(1 + sin x)=1-sin²x=cos²x
Answer:
The second and third line are wrong
Step-by-step explanation:
(4x³ +4x²-8x) -(8x²-16x+4)
= 4x³ +4x²-8x - 8x²+ 16x -4
= 4x³ +4x²- 8x²-8x+ 16x -4
= 4x³ -4x²+ 8x -4
In the second line:
it has to be +16x because - times - is +
it is like -1*(8x²-16x+4)
In the third line:
you can only add or subtract the xs with the same exponentation, so
4x²- 8x² and -8x+ 16x
4x²- 8x²= -4x² not +12x²