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pochemuha
3 years ago
9

Evaluate a. 6! b. 8P5 c. 12C4

Mathematics
1 answer:
erik [133]3 years ago
4 0
I'm pretty sure that the answer is 12C4 = (12p4)/4! = (12*11*10*9)/4*3*2*1 = 495

Hope this helps
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Math question Informatin in dot plots
kozerog [31]

Answer:

Step-by-step explanation:

Range =  difference between the highest and the lowest

Mode = Data that occurs the most time

Median = Arrange  the data in ascending order. The middle data is the median. If number of data is even, median is the average of the two middle  terms.

1) Range = 28 -21 = 7

Mode = 25

Number of data (Count the total dots) = 14

Median = average of  7th and 8th term

Median = (25+25)/2 = 50/2 = 25

2) Range = 0.18 - 0.11 = 0.07

Mode = 0.15 and 0.16

Number of data = 23

Median =12th term = 0.15

8 0
3 years ago
I need help please.
Ira Lisetskai [31]

Answer:

82.5 grams

Step-by-step explanation:

11*7.5=82.5

3 0
3 years ago
Victor has a credit card with an APR of 13.66%, compounded monthly. He currently owes a balance of $1,349.34. Assuming that Vict
konstantin123 [22]
<span>A = P (1 + r/n)^<span>nt
A = </span></span><span>1,349.34(1+0.1366/12)^12
A = 1545.65

answer: </span>he will owe $1545.65 after one year
4 0
4 years ago
Read 2 more answers
I NEED HELP PLEASE ASAP!!!!!
GREYUIT [131]
I’m assuming you’re asking for the areas of the squares?

Since these shapes are all squares, all of the sides of each square is going to have the same length and width. So to find the area all you have to do is multiply each side by itself, for example, multiplying 1.6 by 1.6 to find the area.

The answers from left to right are as follows: 4.84yd, 2.25yd, 2.56yd
8 0
3 years ago
9) If x=-4 is a zero of a polynomial p(x), then the zero of p(x² - 6x + 5) is​
spin [16.1K]

If x=-4 is a zero of p(x), then we can write

p(x) = (x + 4) q(x)

for another polynomial q(x).

Note that x^2 - 6x + 5 = (x - 5)(x - 1). Then

p(x^2 - 6x + 5) = p\bigg((x-5)(x-1)\bigg) \\\\ ~~~~~~~~~~~~ = ((x - 5)(x-1) + 4) q\bigg((x-5)(x-1)\bigg) \\\\ ~~~~~~~~~~~~ = (x^2 - 6x + 9) q(x^2 - 6x + 5) \\\\ ~~~~~~~~~~~~ = (x - 3)^2 q(x^2 - 6x + 5)

so that \boxed{x = 3} is a root of p(x^2 - 6x + 5).

5 0
2 years ago
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