3 years ago

Please help please please please please

1 answer:

5 0

One dice has 6 sides and two dice will give us 12 sides with 36 possibilities
it will be 9/36=.25

so it will have 25% chance of the two dice to have a sum of 9

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Solve the inequality<br> x/3 - 2 <4

Afina-wow [57]

Answer:

brainliest please

Step-by-step explanation:

x/3-2<4

x/3<6

x<18

8 0

3 years ago

Someone please help me I’ll give out brainliest please dont answer if you don’t know

sasho [114]

Answer:

$56.25

Step-by-step explanation:

3% of 750, then multiply by 2.5

6 0

3 years ago

How to factor 6x^2+7x-10

Studentka2010 [4]

the answer is....

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6 0

3 years ago

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The family of solutions to the differential equation y ′ = −4xy3 is y = 1 √ C + 4x2 . Find the solution that satisfies the initi

slega [8]

Answer:

The correct option is 4

Step-by-step explanation:

The solution is given as

$y(x)=\frac{1}{\sqrt{C+4x^2}}$

Now for the initial condition the value of C is calculated as

$y(x)=\frac{1}{\sqrt{C+4x^2}}\\y(-2)=\frac{1}{\sqrt{C+4(-2)^2}}\\4=\frac{1}{\sqrt{C+4(4)}}\\4=\frac{1}{\sqrt{C+16}}\\16=\frac{1}{C+16}\\C+16=\frac{1}{16}\\C=\frac{1}{16}-16$

So the solution is given as

$y(x)=\frac{1}{\sqrt{C+4x^2}}\\y(x)=\frac{1}{\sqrt{\frac{1}{16}-16+4x^2}}$

Simplifying the equation as

$y(x)=\frac{1}{\sqrt{\frac{1}{16}-16+4x^2}}\\y(x)=\frac{1}{\sqrt{\frac{1-256+64x^2}{16}}}\\y(x)=\frac{\sqrt{16}}{\sqrt{{1-256+64x^2}}}\\y(x)=\frac{4}{\sqrt{{1+64(x^2-4)}}}$

So the correct option is 4

8 0

3 years ago

Read 2 more answers

the first four terms of a geometric progression are 2,10,50,250 a) write down the common ratio of the progression b) write down

VLD [36.1K]

Answer:

The common ratio is 5 and the 5th term is 1250

Step-by-step explanation:

The common ratio is given by

r=U(2)/U (1)

=10/2

The fifth term

U (n)=ar^n-1

U(5)=2(5)^5-1

=2×5^4

=2×625

=1250

3 0

3 years ago