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lys-0071 [83]
3 years ago
12

Destiny gives her bean plant 2/3 cup water every day. how much water does destiny give her bean plant in 8 days?

Mathematics
1 answer:
Travka [436]3 years ago
8 0
2/3 times 8 = 16/3 =5 1/3 cups of water.
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15. A jar contains 6 aqua beads and 4 black beads. If two beads are selected
Alex17521 [72]

Answer:

9/25

Step-by-step explanation:

(6/10)(6/10)

= (3/5)(3/5)

=9/25

6 0
3 years ago
A rectangle school banner has a length of 44 inches, a perimeter of 156 inches , and an area of 1496 square inches. The cheerlea
Andrej [43]
Based on the lengths, the cheerleaders' banner is scaled down by a factor of 4.

So, 44 ÷ 4 = 11.

For the perimeter, 156 ÷ 4 is 39.

For the area, you have to do A=bh
(Area = base × height)

The base (length) is 11 inches, multiply that by two to get 22 inches which is the amount for both lengths. If the total perimeter is 39, you have to subtract 22 from that to get the remaining inches which is 17.
17÷2= 8.5 inches. The height is 8.5.

Now you can plug them in
A=bh
A=(11)(8.5)
A=93.5 in^2

The final answer is:
Area = 93.5 in^2
Length = 11 in
Perimeter = 39 in

I hope that helps!
7 0
3 years ago
An equiangular triangle has one side of length six inches. What is the height of the triangle, drawn from that side, to the near
Mandarinka [93]

9514 1404 393

Answer:

  5.2 in

Step-by-step explanation:

An equiangular triangle is also equilateral. All sides will be 6 inches, and the height line will be a perpendicular bisector of the side.

Using trig, the height is ...

  (3 in)tan(60°) = 3√3 in ≈ 5.2 in

Using the Pythagorean theorem, ...

  h² = 6² -3² = 27

  h = √27 ≈ 5.2 . . . inches

6 0
3 years ago
Write log3 6 as a logarithm of base 2.
Sever21 [200]
Use:\\\log_ab=\dfrac{\log_cb}{\log_ca}\ and\ \log_ab+\log_ac=\log_a(bc)\\\\\log_36=\dfrac{\log_26}{\log_23}=\dfrac{\log_2(2\cdot3)}{\log_23}=\dfrac{\log_22+\log_23}{\log_23}\\\\=\dfrac{\log_22}{\log_23}+\dfrac{\log_23}{\log_23}=\boxed{\dfrac{1}{\log_23}+1}\\\\other\ method\\Use:\\\log_ab=\dfrac{1}{\log_ba}\\\\\log_36=\log_3(2\cdot3)=\log_32+\log_33=\log_32+1=\boxed{\dfrac{1}{\log_23}+1}
4 0
3 years ago
I NEED HELP PLEASE 15 POINTS
ra1l [238]

Answer:

20°

Step-by-step explanation:

∡EFJ = 70°

∡JFK = 90°

So, ∡KFG = 180 - ∡JFK - ∡EFJ = 180 - 90 - 70 = 20°

8 0
3 years ago
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