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3 years ago

10

By selling a chair for Rs. 1440 a shopkeeper loses 10%.At what price did he buy it?

2 answers:

fiasKO [112]3 years ago

7 0

1600 rupees. Really hope this answer helps!

Dvinal [7]3 years ago

5 0

Selling price of the chair = 1440 rupees
Percentage of loss made by the shopkeeper = 10%
Let us assume the price at which the shopkeeper bought the chair = x
Then
90% * x = 1440 rupees
(90/100) * x = 1440 rupees
9x/10 = 1440 rupees
9x = 1440 * 10 rupees
9x = 14400 rupees
x = 14400/9 rupees
= 1600 rupees
So the price at which the shopkeeper bought the chair was 1600 rupees. I hope the procedure is clear enough for you to inderstand.

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marysya [2.9K]

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3

Step-by-step explanation:

Given:

Team heights (inches):

61, 57, 63, 62, 60, 64, 60, 62, 63

To find: IQRs (interquartile ranges) of the heights for the team

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A quartile divides the number of terms in the data into four more or less equal parts that is quarters.

For a set of data, a number for which 25% of the data is less than that number is known as the first quartile $(Q_1)$

For a set of data, a number for which 75% of the data is less than that number is known as the third quartile $(Q_3)$

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$57,60,60,61,62,62,63,63,64$

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As number of terms is odd, exclude the middle term that is 62.

$Q_1$ is median of terms $57,60,60,61$

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So, $Q_1=60$

So, 25% of the heights of a team is less than 60 inches

$Q_3$ is the median of terms $62,63,63,64$

Median = $\frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th} }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{63+63}{2}=\frac{126}{2}=63$

So, $Q_3=63$

So, 75% of the heights of a team is less than 63 inches

Interquartile range = $Q_3-Q_1=63-60=3$

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