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WITCHER [35]
3 years ago
13

Which statements are true for solving the equation 0.5 – |x – 12| = –0.25? Check all that apply.

Mathematics
2 answers:
earnstyle [38]3 years ago
5 0

Answer:

2. A good first step for solving the equation is to subtract 0.5 from both sides of the equation.

5. The negative case of this equation is x – 12 = –0.75.

Trava [24]3 years ago
4 0

we have  

0.5-\left|x-12\right|=-0.25  

we know that        

The absolute value has two solutions

Subtract  0.5 both sides

-\left|x-12\right|=-0.25-0.5  

-\left|x-12\right|=-0.75  

Step 1

Find the first solution (Case positive)

-[+(x-12)]=-0.75

-x+12=-0.75

Subtract  12 both sides

-x+12-12=-0.75-12

-x=-12.75

Multiply by -1 both sides

x=12.75

Step 2

Find the second solution (Case negative)

-[-(x-12)]=-0.75

x-12=-0.75

Adds  12 both sides

x=-0.75+12

x=11.25

<u>Statements</u>

<u>case A)</u> The equation will have no solutions

The statement is False

Because the equation has two solutions------> See the procedure

<u>case B)</u> A good first step for solving the equation is to subtract 0.5 from both sides of the equation

The statement is True ----->  See the procedure

<u>case C)</u> A good first step for solving the equation is to split it into a positive case and a negative case

The statement is False ----->  See the procedure

case D) The positive case of this equation is 0.5 – |x – 12| = 0.25

The statement is False

Because the positive case is 0.5-(x-12)=-0.25 -----> see the procedure

case E) The negative case of this equation is x – 12 = –0.75

The statement is True -----> see the procedure

<u>case F)</u> The equation will have only 1 solution

The statement is False

Because The equation has two solutions------> See the procedure


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I need help with #39-42, please explain.
shusha [124]

For question 39 & 40, we need to use the below equation to complete the sentence

l=m\sqrt{n}

Question 39:

When ' n ' increase, the \sqrt{n} will also increase and that multiplied with constant ' m ', the l will also increase.

Solution for question 39:

As n increases and m stays constant , l <u>increases</u>

-------

Question 40:

Solving the equation for m, we get

l = m\sqrt{n} \\ \\ m=\frac{l}{\sqrt{n}}

When ' l ' increases, the numerator increase, the denominator stays constant because 'n' stays constant, for this condition, the fraction increases.

Solution for question 40:

As l increase and n stays constant, m <em><u>increases</u></em>

------

For question 41 & 42, we need to use the below equation to complete the sentence

r=s^2/t^2

Question 41:

When s is triped, the equation will be...

r=(3s)^2/t^2=\frac{3^{2}s^{2}}{t^2}   =9s^2/t^2

Solution for question 41:

If s is tripled and t stays constant, r is multiplied by <em><u>9</u></em>

--------

Question 42:

When t is doubled, the equation will be...

r=s^2/(2t)^2=\frac{s^2}{2^2 \cdot t^2}=\frac{s^2}{4t^2}\\   \\ r=0.25s^2/t^2 \; \; (or) \; \; \frac{1}{4} \cdot \frac{s^2}{t^2}

Solution for 42:

If t doubled and s stays constant, r is multiplied by <em><u>1/4 or 0.25</u></em>


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3 years ago
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Feliz [49]
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8 0
3 years ago
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anyanavicka [17]

Answer:

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Step-by-step explanation:

For this problem, we simply will solve the inequality for x.

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