1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kkurt [141]
3 years ago
15

Which of the following is the equation for the line of symmetry in this figure?

Mathematics
1 answer:
pochemuha3 years ago
5 0

Answer:

y = -2

Step-by-step explanation:

This one is easy. As you may know, a axis of symmetry is the line where everything is the same on both sides of it. For this, you can use trial and error or just look at the points on either side. For y = -1, that will put the line in an awkward spot, crossing through 2 slanted lines instead of corners. For x = -1, this just cuts through the shape straight up and down and does not make the shape look equal on both sides of the line at all. Same goes for x = -2. I should probably mention, when you see a line that is described as "x = 1", it is a vertical line, because the line is constantly staying on the point x = 1, while having an infinite number of y-values. When you see "y = 1", it will be horizontal for the same reason, just flipped.

You might be interested in
Jorge bought a crate of floor tiles for $95.94.The Crate had six boxes of floor tiles.Each Box contained 20 floor tiles.Write an
Natasha_Volkova [10]

Answer:Cost per box: $95.94 ÷ (b)

            Cost per tile: [$95.94 ÷ (b)]÷ (t)

First, we are trying to find the cost of each crate. Since the whole order was $95.94, we have to divide. The answer to the cost per box is $15.99.

Second, we are trying to find the cost of each of the tiles in the crates. Since they are in each crate, we divide the crate price from the tiles. The answer of the cost per tile is $.80.

Hope this helped you out!

6 0
3 years ago
Qbjsksnnfkkdnnwnnsiodnnjfkjbbskkxkkdn
iris [78.8K]

Answer:

There are 25 students in the class.

Step-by-step explanation:

Since we know the percentage of students who want an ice cream party is 20%, and 5 students want an ice cream party, we know that:

\frac{5}{S}=0.2

, where S is the total amount of students. We can then solve for S:

\frac{5}{S}=0.2 Given equation

5=0.2*S Multiply by S

25=S Divide by 0.2

Therefore, there are 25 students in the class.

7 0
2 years ago
Read 2 more answers
Simplify this expression <br> 7z+5+6z-9
Simora [160]

Answer:

7z + 5 + 6z - 9  (Add 7z and 6z, subtract 9 from 5)

<em>13z - 4  </em>(Can't be simplified further)

8 0
2 years ago
One pound of candies costs $3.50. How much will we have to pay for 3 lb?
Romashka-Z-Leto [24]

Answer: 10.50 dollars


Step-by-step explanation:

3.50 x 3 = 10.50

8 0
3 years ago
Is 0.84 less than greater than or equal to one half
Neporo4naja [7]
One half is 0.50, so compare 0.84 to 0.50.  Which is true?

0.84 is greater than 0.50
0.84 equals 0.50
0.84 is less than 0.50.

8 0
3 years ago
Read 2 more answers
Other questions:
  • Solve this problem T=u+v/2 solve for u
    7·1 answer
  • Which expressions are a factor of -48xyz -24xy +40xyz?
    10·2 answers
  • A tree grows 9.25 inches per year. If the tree continues to grow at this rate, how much will the tree grow in 3.75 year.
    5·1 answer
  • Express the following relations in the set builder notation. Then, determine whether it is reflexive, symmetric, transitive. Ple
    7·1 answer
  • The ratio of two numbers is 5 to 4. The sum of the numbers is 99. What number is the greater of the two numbers?
    5·1 answer
  • If the blue radius below is perpendicular to the chord AC, which is 6 units long, what is the length of the segment AB?
    6·1 answer
  • What is a equivalent ratio to 12/18
    14·1 answer
  • Thomas buys tickets for his family to see a movie.
    11·2 answers
  • Please help me please help me if you don't know gently move your hand
    5·1 answer
  • Please help asap for a math test
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!