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kkurt [141]
3 years ago
15

Which of the following is the equation for the line of symmetry in this figure?

Mathematics
1 answer:
pochemuha3 years ago
5 0

Answer:

y = -2

Step-by-step explanation:

This one is easy. As you may know, a axis of symmetry is the line where everything is the same on both sides of it. For this, you can use trial and error or just look at the points on either side. For y = -1, that will put the line in an awkward spot, crossing through 2 slanted lines instead of corners. For x = -1, this just cuts through the shape straight up and down and does not make the shape look equal on both sides of the line at all. Same goes for x = -2. I should probably mention, when you see a line that is described as "x = 1", it is a vertical line, because the line is constantly staying on the point x = 1, while having an infinite number of y-values. When you see "y = 1", it will be horizontal for the same reason, just flipped.

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Answer:

nuber 1

Simplifying

3x + 2y = 35

Solving

3x + 2y = 35

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2y' to each side of the equation.

3x + 2y + -2y = 35 + -2y

Combine like terms: 2y + -2y = 0

3x + 0 = 35 + -2y

3x = 35 + -2y

Divide each side by '3'.

x = 11.66666667 + -0.6666666667y

Simplifying

x = 11.66666667 + -0.6666666667y

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2 years ago
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Write a polynomial equation of degree 4 in standard form that has the solutions i, −i, 1, −1.
Brut [27]

Answer:

x⁴ + 2 x² + 1

Step-by-step explanation:

given solution of the polynomial

i, −i, 1, −1.                        

equation of the polynomial will be equal to

 =(x - i)(x + i)(x - 1)(x + 1)                      

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Step-by-step explanation:

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Novosadov [1.4K]
<h3>Question:</h3>

find the slope (-8,10) (8,15)

<h3>Answer:</h3>

m = \frac{5}{16}

<h3>Step-by-step explanation:</h3>

Use the slope formula \frac{y2-y1}{x2-x1}

(x2,y1) = (-8,10) , (x2,y2) = (8,15)

m = \frac{15-10}{8-(-8)}

m = \frac{5}{16}

Hope this helps :)

Please consider marking my answer brainlist!

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