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lana [24]
3 years ago
12

Find the GCF of n 3 t 2 and nt 4.

Mathematics
2 answers:
borishaifa [10]3 years ago
7 0
The GCF is 1

Hope this helps
Tanzania [10]3 years ago
3 0
The answer is 1 the gcf is 1...............


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A is 5 years older than T. In 3 years, T will be 2/3 A age. How old is A?
Ivanshal [37]

Answer:

12 years

Step-by-step explanation:

T + 5 = A

Therefore T =A - 5

In three years T = 3+ (A-5)

thus T = A - 2

Also in three years T = 2/3 (A+3)

Equating the two

A -2 = 2/3 (A+3)

3A - 6 = 2A + 6

3A - 2A = 6 + 6

Therefore A = 12

6 0
3 years ago
Can I get another answer please ?
gavmur [86]
G(x) = x^2 + 2x + 6
g(x) = x^2 + 2x + 1 + 5
g(x) = (x+1)^2  + 5

so
f(x) = x^2 to g(x) = (x+1)^2  + 5
shifted to the left 1 unit and up 5 units

answer is A. left 1 unit and up 5 units
4 0
3 years ago
Please help i don’t understand this
avanturin [10]

Answer:

Step-by-step explanation:

The solution is in the attached file

3 0
2 years ago
A box contains 3 coins. One coin has 2 heads and the other two are fair. A coin is chosen at random from the box and flipped. If
Blababa [14]

Answer: Our required probability is \dfrac{1}{2}

Step-by-step explanation:

Since we have given that

Number of coins = 3

Number of coin has 2 heads = 1

Number of fair coins = 2

Probability of getting one of the coin among 3 = \dfrac{1}{3}

So, Probability of getting head from fair coin = \dfrac{1}{2}

Probability of getting head from baised coin = 1

Using "Bayes theorem" we will find the probability that it is the two headed coin is given by

\dfrac{\dfrac{1}{3}\times 1}{\dfrac{1}{3}\times \dfrac{1}{2}+\dfrac{1}{3}\times \dfrac{1}{2}+\dfrac{1}{3}\times 1}\\\\=\dfrac{\dfrac{1}{3}}{\dfrac{1}{6}+\dfrac{1}{6}+\dfrac{1}{3}}\\\\=\dfrac{\dfrac{1}{3}}{\dfrac{2}{3}}\\\\=\dfrac{1}{2}

Hence, our required probability is \dfrac{1}{2}

No, the answer is not \dfrac{1}{3}

5 0
3 years ago
Hey! yes you! can you help me with this? I will give brainliest! ​
KonstantinChe [14]

Answer:

the answer is h

Step-by-step explanation:

7 0
3 years ago
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