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miskamm [114]
4 years ago
13

Give an example of a number that is a perfect square and also a perfect cube.

Mathematics
2 answers:
Vanyuwa [196]4 years ago
6 0

Answer:

64

Step-by-step explanation:

\sqrt{64} \\=8

\sqrt[3]{64}=4

scoundrel [369]4 years ago
3 0
The answer is 64 and 729
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Find the values of the Vertex and Axis of symmetry.
Ipatiy [6.2K]

Answer:

it is none of my business ~(つˆДˆ)つ。☆~(つˆДˆ)つ。☆(っ.❛ ᴗ ❛.)っ(っ.❛ ᴗ ❛.)っ(っ.❛ ᴗ ❛.)っ

4 0
3 years ago
Evaluate the integral Integral from (5 comma 2 comma 4 )to (7 comma 9 comma negative 3 )y dx plus x dy plus 3 dz by finding para
padilas [110]

\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\int_{(5,2,4)}^{(7,9,-3)}y\,\mathrm dx+x\,\mathrm dy+3\,\mathrm dz

Parameterize the line segment (call it C) by

\vec r(t)=(1-t)(5\,\vec\imath+2\,\vec\jmath+4\,\vec k)+t(7\,\vec\imath+9\,\vec\jmath-3\,\vec k)

\vec r(t)=(2t+5)\,\vec\imath+(7t+2)\,\vec\jmath+(4-7t)\,\vec k

with 0\le t\le1. Then

\vec r'(t)=2\,\vec\imath+7\,\vec\jmath-7\,\vec k

and the line integral is

\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\int_0^1((7t+2)\,\vec\imath+(2t+5)\,\vec\jmath+3\,\vec k)\cdot\vec r'(t)\,\mathrm dt

=\displaystyle\int_0^1((2t+5)+2(7t+2)-21)\,\mathrm dt

=\displaystyle\int_0^1(28t+18)\,\mathrm dt=\boxed{32}

Alternatively, if we can show that \vec F is conservative, then we can apply the fundamental theorem of calculus. We need to find f such that \nabla f=\vec F, which requires

\dfrac{\partial f}{\partial x}=y

\dfrac{\partial f}{\partial y}=x

\dfrac{\partial f}{\partial z}=3

Integrating both sides of the first equation with respect to x gives

f(x,y,z)=xy+g(y,z)

Differentiating both sides wrt y gives

\dfrac{\partial f}{\partial y}=x=x+\dfrac{\partial g}{\partial y}

\implies\dfrac{\partial g}{\partial y}=0\implies g(y,z)=h(z)

Differentiating wrt z gives

\dfrac{\partial f}{\partial z}=3=\dfrac{\mathrm dh}{\mathrm dz}

\implies h(z)=3z+C

So we have

f(x,y,z)=xy+3z+C

and \vec F is conservative. By the FTC, we find

\displaystyle\int_C\vec F\cdot\mathrm d\vec r=f(7,9,-3)-f(5,2,4)=\boxed{32}

5 0
3 years ago
A high school statistics class wants to estimate the average number of chocolate chips in a generic brand of chocolate chip cook
Viktor [21]

Answer:

Correct option:

We are 95% certain that the confidence interval of 18.6 to 21.3 includes the true average number of chocolate chips per cookie.

Step-by-step explanation:

The general formula for the (1 - <em>α</em>)% confidence interval for population<em> </em>mean is:

CI=\bar x\pm CV \times SE_{\bar x}

Here:

\bar x = sample mean

CV = critical value

SE_{\bar x} = standard error of mean.

The (1 - <em>α</em>)% confidence interval for population parameter implies that there is a (1 - <em>α</em>) probability that the true value of the parameter is included in the interval.

Or, the (1 - <em>α</em>)% confidence interval for the parameter implies that there is (1 - <em>α</em>)% confidence or certainty that the true parameter value is contained in the interval.

The 95% confidence interval for the mean number of chocolate chips per cookie is (18.6, 21.3).

This 95% confidence interval implies that there is a 0.95 probability that the true mean number of chocolate chips per cookie is between 18.6 and 21.3.

Thus, the correct option is:

"We are 95% certain that the confidence interval of 18.6 to 21.3 includes the true average number of chocolate chips per cookie. "

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Answer:

1mm, 1cm, 1m, 1km.

Step-by-step explanation:

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