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3 years ago

Which is the correct path of light through a reflecting telescope?

Physics

2 answers:

iris [78.8K]3 years ago

5 0

Answer:

B.) Primary mirror--->secondary mirror--->eyepiece--->eye

Explanation:

i jusk took the test here's a pic for proof. (please mark brainliest)

NikAS [45]3 years ago

5 0

Answer:

B.) Primary mirror--->secondary mirror--->eyepiece--->eye

Explanation:

Hope this helps : )

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For free convection from a surface to the ambient fluid, an increase in Grashof number

Kipish [7]

Answer: Option(d) is the correct option

Explanation:

Grashof number (Gr) is the ratio that is between buoyant force to viscous force persist on fluid on layer of velocity boundary.It is in dimensionless form.

According to the question ,

Laminar flow has $10^{3}$ < (Gr) < $10^{6}$ as range of boundary layer for free convection.

For transition to take place into turbulent form, it has range of $10^{8} < Gr < 10^{9}$ in terms of free convection.

So, if Grashof number (Gr) is increased then it might tend to change flow from laminar form into turbulent form for free convection.

Other options are incorrect because increasing in Grashof number does not always change the flow mechanism from laminar to turbulent or vice versa neither may cause to laminar flow. Therefore, the correct option is option(d).

4 0

4 years ago

While running a 100m race, a runner runs from the 20m to 30m mark in 77 frames of a video record. If the video camera recorded d

Marrrta [24]

Answer:

Speed of the runner during video interval is 6.49 m/s

Explanation:

According to the problem,

Number of frames recorded by camera in 1 second = 50

Time takes by camera to record 1 frame = (1/50) s

Time taken by camera to record 77 frames, t = $\frac{1}{50}\times 77$ s

Distance covered by the runner during the video recording, d = 10 m

Speed, v = $\frac{Distance}{time}=\frac{d}{t}$

Substitute the values of d and t in the above equation.

v = $\frac{10}{\frac{77}{50} }$

v = 6.49 m/s

3 0

4 years ago

What type of wave can be seen by the human eye

Svetach [21]

Light can be seen by the human eye

3 0

4 years ago

Read 2 more answers

A motorcycle cover a distance of 1.8 km in 5 minute. calculate its average velocity?

OlgaM077 [116]

Answer:

$solution \\ distance \: travelled = 1.8 \: km \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 1.8 \times 1000m \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 1800 \: m \\ time \: taken = 5 \: minute \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 5 \times 60 \: seconds \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 300 \: seconds \\ average \: velocity = \frac{distance \: travelled}{time \: taken} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{1800}{ 300} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 6 \: {ms}^{ - 1}$

hope this helps..

8 0

3 years ago

Read 2 more answers

A car travels at a constant rate for 100 miles going due west for one hour. Then it travels at a constant rate for another 75 mi

nirvana33 [79]

Answer:

C. 100 mph west

Explanation:

Average velocity is total displacement over total time. During the first hour, the average velocity is:

v_avg = 100 mi / 1 hr

v_avg = 100 mph west

Since the velocity is constant, the instantaneous velocity at any time equals the average velocity.

v = v_avg

v = 100 mph west

7 0

4 years ago