Answer:
2
Explanation:
We know that in the Fraunhofer single-slit pattern,
maxima is given by
![a\text{sin}\theta=\frac{2N+1}{2}\lambda](https://tex.z-dn.net/?f=a%5Ctext%7Bsin%7D%5Ctheta%3D%5Cfrac%7B2N%2B1%7D%7B2%7D%5Clambda)
Given values
θ=2.12°
slit width a= 0.110 mm.
wavelength λ= 582 nm
Now plugging values to calculate N we get
![0.110\times10^{-3}\text{sin}2.12=(\frac{2N+1}{2})582\times10^{-9}](https://tex.z-dn.net/?f=0.110%5Ctimes10%5E%7B-3%7D%5Ctext%7Bsin%7D2.12%3D%28%5Cfrac%7B2N%2B1%7D%7B2%7D%29582%5Ctimes10%5E%7B-9%7D)
Solving the above equation we get
we N= 2.313≅ 2
Answer:
They are conductors/conductive. Materials that can transfer thermal energy well are conductive.
Explanation:
Answer:
∑Fy = 0, because there is no movement, N = m*g*cos (omega)
Explanation:
We can solve this problem with the help of a free body diagram where we show the respective forces in each one of the axes, y & x. The free-body diagram and the equations are in the image attached.
If the product of mass by acceleration is zero, we must clear the normal force of the equation obtained. The acceleration is equal to zero because there is no movement on the Y-axis.
Answer:
≅50°
Explanation:
We have a bullet flying through the air with only gravity pulling it down, so let's use one of our kinematic equations:
Δx=V₀t+at²/2
And since we're using Δx, V₀ should really be the initial velocity in the x-direction. So:
Δx=(V₀cosθ)t+at²/2
Now luckily we are given everything we need to solve (or you found the info before posting here):
- Δx=760 m
- V₀=87 m/s
- t=13.6 s
- a=g=-9.8 m/s²; however, at 760 m, the acceleration of the bullet is 0 because it has already hit the ground at this point!
With that we can plug the values in to get:
![760=(87)(cos\theta )(13.6)+\frac{(0)(13.6^{2}) }{2}](https://tex.z-dn.net/?f=760%3D%2887%29%28cos%5Ctheta%20%29%2813.6%29%2B%5Cfrac%7B%280%29%2813.6%5E%7B2%7D%29%20%7D%7B2%7D)
![760=(1183.2)(cos\theta)](https://tex.z-dn.net/?f=760%3D%281183.2%29%28cos%5Ctheta%29)
![cos\theta=\frac{760}{1183.2}](https://tex.z-dn.net/?f=cos%5Ctheta%3D%5Cfrac%7B760%7D%7B1183.2%7D)
![\theta=cos^{-1}(\frac{760}{1183.2})\approx50^{o}](https://tex.z-dn.net/?f=%5Ctheta%3Dcos%5E%7B-1%7D%28%5Cfrac%7B760%7D%7B1183.2%7D%29%5Capprox50%5E%7Bo%7D)