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Soloha48 [4]
3 years ago
10

What value from the set {1, 2, 3, 4, 5} make the equality true? n + 2 < 6

Mathematics
2 answers:
s344n2d4d5 [400]3 years ago
7 0
1-3 are all less than 6
Black_prince [1.1K]3 years ago
6 0
1, 2, and 3 all do. 4 and 5 don't.
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Find the value of the angle θ rounded to 1 DP.
kogti [31]

Answer:

Step-by-step explanation:

Sin 21 = \frac{opposite side}{hypotenuse}

Sin 21 = \frac{BC}{15}

0.3583 = \frac{BC}{15}

0.3583*15 = BC

BC = 5.3745 = 5.37 m

Tan ∅ = \frac{opposite side}{adjacent side}

Tan ∅ = \frac{4}{5.37}= 0.7448

∅ = tan⁻¹ (0.7448) = 36.67 = 36.7

5 0
2 years ago
Y-3=5x solveeeeeeeeeeeeeeeeeeeeeeeeeeeee
Stella [2.4K]

Answer:

y=5x+3 that's the right answer i swear(:

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
56 in²
garri49 [273]

The area of the remaining board is [(L × B) - (l × b)].

According to the statement

We have to find that the area of the remaining board.

So, For this purpose, we know that the

Area of rectangle is the region occupied by a rectangle within its four sides or boundaries. The area of a rectangle depends on its sides.

From the given information:

Suppose the bigger rectangle is labelled as ABCD and the smaller rectangle is labelled as PQRS.

And

Consider that the length and breadth of the bigger rectangle are L and B respectively. And the length and breadth of the bigger rectangle are l and b respectively.

The area of any rectangle is:

Area = Length × Breadth

The area of the bigger rectangle is:

Area of ABCD = L × B

The area of the smaller rectangle is:

Area of PQRS = l × b

Then the area of the remaining board will be:

Area of remaining board = Area of ABCD - Area of PQRS

Area of remaining board= (L × B) - (l × b)

Thus, The area of the remaining board is [(L × B) - (l × b)].

Learn more about Area here

brainly.com/question/8409681

Disclaimer: This question was incomplete. Please find the full content below.

Question:

A rectangle is removed from the middle of a larger rectangular shaped board. What is the area of the remaining board?

#SPJ9

6 0
1 year ago
Write 894,217 in expended form an using number names
storchak [24]
Eight hundred ninety four thousand, two hundred and seventeen. I hope this helps.
5 0
3 years ago
I'd really appreciate some help on these questions, I'm really struggling
nikklg [1K]
We can use linear combinations of the equations to eliminate variables.

3x - 4y = 1
-2x + 3y = 1

To eliminate y we'll make the linear combination of 3 times the first equation minus four times the second. 

9x - 12y = 3
-8x + 12y = 4

Adding,
x = 7

We could solve for y directly but let's use another linear combination, twice the first plus three times the second:

2(3x - 4y) + 3(-2x + 3y)= 2(1)+3(1)

y = 5

Check: 3(7)-4(5)=1 good.   -2(7)+3(5)=1 good.

Q18 Answer: (7,5)

y = -3x + 5
5x - 4y = -3

4y +1(5x - 4y) = 4(-3x + 5) + 1(-3)

5x = -12x + 20 -3

17 x = 17

x = 1
y = -3(1) + 5 = 2
Check: 5(1) - 4(2) = -3 good

Q19 Answer (1,2)

6x + 5y = 25
x = 2y + 24
6x = 12y + 144
5y = 25 - 12y - 144
17y = -119
y = -119/17= -7
x = 2y+24= 10
Check: 6(10)+5(-7)=25 good   2y+24=2(-7)+24=10=x good

Q20 Answer (10,-7)


3x + y = 18
-7x + 3y = -10
9x  + 3y = 54
9x - -7x = 54 - -10
16x = 64
x=4
y = 18 -3x = 18-12=6

Check: 3(4)+6=18 good,  -7(4)+3(6)=-10 good

Q21 Answer: (4,6)

6 0
3 years ago
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