What value from the set {1, 2, 3, 4, 5} make the equality true? n + 2 < 6
2 answers:
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9514 1404 393
Answer:
the origin
Step-by-step explanation:
Both terms are of odd degree, so the function is an odd function. It is symmetrical with respect to the origin.
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If you recast this as y = f(x), then ...
f(x) = x^(3/5)
When we look at f(-x), we find ...
f(-x) = ((-x)^3)^(1/5) = -(x^3)^(1/5) = -(x^(3/5)) = -f(x)
An odd root of a number has the same sign as the number.
When f(-x) = -f(x), the function is odd and symmetrical about the origin.
Answer:
there are two solutions:
a) , and
b)
Step-by-step explanation:
In the equation: , since a perfect square with the unknown "y" is isolated on the left of the equal sign, we start by applying the square root on both sides of the equality, and then on isolating the unknown:
Therefore there are two solutions:
a) , and
b)