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vovikov84 [41]
4 years ago
15

In the military, 1/4 of an enlisted person's time is spent sleeping and eating, 1/12 is spent standing at attention, 1/6 is spen

t staying fit, and 2/5 is spent working. The rest of the time is spent at the enlisted person's own discretion. How many hours per day does this discretionary time amount to?
Mathematics
1 answer:
IRINA_888 [86]4 years ago
5 0
All you have to do is add all of the fractions up.
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Find |−68|. plz i will give brainlist
Anni [7]

Answer:

68

Step-by-step explanation:

The lines on both sides of the number represent absolute value. Absolute value takes any number and turns it positive no matter what.

|-68| → 68

Best of Luck!

8 0
3 years ago
PLEASE ANSWER I WILL MARK AS BRAINLIEST
Tomtit [17]

Answer:

Six

Step-by-step explanation:

1.Convert all volumes to millilitres

(a) Chlorpheniramine

V = 100 mL

(b) Lidocaine

V = \text{2 fl oz} \times \dfrac{\text{29.57 mL}}{\text{1 fl oz}} = \textbf{59 mL}

(c) Banana flavouring

V = \dfrac{1}{2}\text{ tsp} \times \dfrac{\text{4.928 mL}}{\text{1 tsp}} = \textbf{2.5 mL }

2. Calculate the total volume

Chlorpheniramine = 100  mL

Lidocaine               =   59

Banana flavouring =  <u>   2.5    </u>

TOTAL                    =  162 mL

3. Calculate the number of doses

\text{Doses} = \text{162 mL} \times \dfrac{\text{1 dose}}{\text{10 mL}} = \text{16.2 doses}\\\\\text{You can't take a fraction of a dose, so the there are $\large \boxed{\textbf{16 doses}}$}

5 0
3 years ago
40% of Oatypop cereal boxes contain a prize. Hannah plans to keep buying cereal until she gets a prize. What is the probability
aleksley [76]

Answer:

(0.6)^{n}+n(0.4)(0.6)^{n-1}+\frac{n(n-1)(0.4)^{2}0.6^{n-2}}{2} +\frac{n(n-1)(n-2)0.4^{3}0.6^{n-3}}{6}

Step-by-step explanation:

We will use the binomial distribution. Let X be the random variable representing the no. of boxes Hannah buys before betting a prize.

Our success is winning the prize, p =40/100 = 0.4

Then failure q = 1-0.4  = 0.6

Hannah keeps buying cereal boxes until she gets a prize. Then n be no. times she buys the boxes.

P(X ≤ 3) = P(X=0) +P(X=1)+P(X=2)+P(X=3)

             = \binom{n}{0}p^{0}q^{n-0} +  \binom{n}{1}p^{1}q^{n-1}+ \binom{n}{2}p^{2}q^{n-2}+ \binom{n}{3}p^{3}q^{n-3}


             =  q^{n}+npq^{n-1}+\frac{n(n-1)(p)^{2}q^{n-2}}{2}+\frac{n(n-1)(n-2)p^{3}q^{n-3}}{6}

             = (0.6)^{n}+n(0.4)(0.6)^{n-1}+[tex]\frac{n(n-1)(0.4)^{2}0.6^{n-2}}{2} +\frac{n(n-1)(n-2)0.4^{3}0.6^{n-3}}{6}


7 0
3 years ago
Read 2 more answers
So, the question on my test was a pair of in line skates is on sale for 90. if this price represents a 9% discount from the orig
crimeas [40]
Pay attention in class
5 0
3 years ago
How many lines of symmetry does a regular decagon have?<br><br> 8<br><br> 10<br><br> 11<br><br> 12
bixtya [17]
The number of sides is the same as the number of lines of symmetry and the order of rotational symmetry.

So, a regular decagon would have 10 lines of symmetry.
6 0
4 years ago
Read 2 more answers
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