Can anyone help me wit this!!
1 answer:
Answer:
- See attachment for table values
- y₁ = y₂ for x = 6
Step-by-step explanation:
In each case, put the x-value in the formula and do the arithmetic. If you're allowed, you can save some time and effort by realizing that the solution (x) will have to be an even number.
y₁ is an integer value for all integer values of x. y₂ is an integer value for even values of x only. y₁ and y₂ will both be integers (and possibly equal) only when x is even.
For example, for x = 6, we have
... y₁ = 3·6 - 8 = 18 -8 = 10
... y₂ = 0.5·6 +7 = 3 +7 = 10
That is, for x = 6, both columns of the table have the same number (10). That is, y₁ = y₂ for x = 6. The solution to the equation
... y₁ = y₂
is
... x = 6.
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Answer:
1i) nth term = 12(-b/4)^(n-1)
ii) nth term = 3(-1/9)^(n-1)
2i) Sixth term= (-3b^5)/256
ii) Eight term = -1/1594323
Question:
The complete question as found on brainly (question-10746111):
Write down the nth term of each of the following G.Ps whose first two terms are given as follows. Also find the term stated besides each G.P.
i) 12,-3b,......sixth term
ii) 3,-1/3,..........;8th term?
Step-by-step explanation:
1) To solve terms involving Geometric progressions (GPs), we would first state the variables that are to be incorporated in the formula.
i) 12,-3b,......;sixth term
1st term = a= 12
r = common ratio = 2nd term /1st term
r = -3b/12 = -b/4
Then we would find the nth term
See attachment for details
ii) 3,-1/3,..........;8th term
1st term = a= 3
r = common ratio = 2nd term /1st term
r = (-⅓)/3 = (-⅓)(⅓) = -1/9
Then we would find the nth term
See attachment for details
2) we are to determine the sixth term in (i) and eight term in (ii)
See attachment for details
Sixth term= (-3b^5)/256
Eight term = -1/1594323
Answer:
0.53%
Step-by-step explanation:
hope it is well understood
