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3 years ago

11

Describe a sequence of reflections, rotations, and translations that shows that quadrilateral ABCD is congruent to quadrilateral

EFGH.

1 answer:

rusak2 [61]3 years ago

3 0

Answer:

Rotate it counterclockwise then reflect it across the Y-axis

hope this helped :)

Step-by-step explanation:

You might be interested in

(1) a) 5270 cl= ? dal

Ivanshal [37]

Answer:

Check below

Step-by-step explanation:

1) These metric volume units can be easily converted by dividing or multiplying by 10 and its multiple. Like this: each step up on the ladder multiply by 10. Each step down divide by 10

$a)5270 \:cl=527\:dl\\b)kl=5.3 \times 10=530 hl\\c)58000ml=5.8 dal =(\frac{58000}{10000})\\d)0.39 dal=3.9 l\\e)7.8 dal=780 dl\\f)57.2 ml=5.72 cl$ .

2) When it comes to area, the "ladder scheme" remains valid but now we'll multiply or divide by

$10^3$

Bear in mind these useful relations:

$1litre =\frac{1}{10^3}m^{3}$

$1 cm^{3} =1 ml$

$a) 3.7 l=3700 cm^{3}\\b)29.6 dm^{3}\\29.6 dm^{3} \rightarrow 29.6\times10^{3} cm^3=29.6\times10^{3} ml = 29.6\times10^{2} cl \:or\:2960 cl\\c)8.1l=8100 cm^{3}\\d)5l=\frac{5}{10^{-3}} m^{3}\\e)5.2 cl=52ml=52 cm^{3}=52\times10^{3}=52000 \:mm^{3}\\f)375 ml=375 cm^{3}\\g) 1300 cm^{3}=1300 ml=13 dl\\h) 8.6 ml= 8.6 cm^{3}\times\: 10^{3}=8600 mm^{3}\\i) 51.8\times 10^{11} l \rightarrow 51.8\times 10^{-11}km^{3}$

6 0

3 years ago

A train leaves Buffalo traveling west at 60 miles per hour. An hour later, another train leaves Buffalo traveling east at 80 mil

kozerog [31]

The two trains the same distance from Buffalo is 20

8 0

3 years ago

Say a friend had multiplied 1.2 and 2.6 and got 31.2. would that be the correct answer

VLD [36.1K]

No 1.2 x 2.6 doesn't equal 31.2 it equals 3.12

6 0

3 years ago

Algebra identify the pattern. Then write the next three terms in each sequence. 63,58,53,48.....

vovikov84 [41]

Answer:43, 38, 33

Step-by-step explanation:

The pattern is subtracting 5

63 -5 = 58

58 - 5 = 53

53 - 5 = 48

48 - 5 = 43

43 - 5 = 38

38 - 5 = 33

8 0

3 years ago

what is the volume of a oblique cylinder with the height of 6 cm and a 4 cm as the radius of its base

JulsSmile [24]

Answer :

301.44 cm³

⠀

Explanation :

We know,

${ \longrightarrow \qquad\pmb {\boldsymbol{ Volume_{(cylinder)} = \pi {r}^{2} h \: }}}$

Where,

<em>r</em> is the radius of the cylinder. Here, the radius is 4 cm

<em>h</em> is the height of the cylinder. Here, height is 6 cm

Here, we will take the value of π as 3.14 approximately .

⠀

Substituting the values in the formula :

⠀

${ \longrightarrow \qquad{ \ { \sf{ Volume_{(cylinder)} \it {= 3.14 \times ({4})^{2} \times 6 \: }}}}}$

⠀

${ \longrightarrow \qquad{ \ { \sf{ Volume_{(cylinder)} \it {= 3.14 \times 16\times 6 \: }}}}}$

⠀

${ \longrightarrow \qquad{ \ { \sf{ Volume_{(cylinder)} \it {= 3.14 \times 96 \: }}}}}$

⠀

${ \longrightarrow \qquad{ \ { \it{ \pmb{ Volume_{(cylinder)} {= 301.44 \: }}}}}}$

⠀

Therefore,

The volume of the cylinder is 301.44 cm³ approximately.

6 0

2 years ago

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