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3 years ago

7

Help on math? Thanks

1 answer:

Flauer [41]3 years ago

3 0

The answer to this is 58 in

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The coordinates of the vertices of a polygon are (-2, 1). (-3, 3), (-1, 5), (2, 4), and (2, 1). What is the perimeter of the pol

kobusy [5.1K]

Answer:

$15.2\ units$

Step-by-step explanation:

step 1

Plot the vertices of the polygon to better understand the problem

we have

$A(-2, 1). B(-3, 3), C(-1, 5), D(2, 4),E(2, 1)$

using a graphing tool

The polygon is a pentagon (the number of sides is 5)

see the attached figure

The perimeter is equal to

$P=AB+BC+CD+DE+AE$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

step 2

<em>Find the distance AB</em>

$A(-2, 1). B(-3, 3)$

substitute in the formula

$d=\sqrt{(3-1)^{2}+(-3+2)^{2}}$

$d=\sqrt{(2)^{2}+(-1)^{2}}$

$d_A_B=\sqrt{5}=2.24\ units$

step 3

<em>Find the distance BC</em>

$B(-3, 3), C(-1, 5)$

substitute in the formula

$d=\sqrt{(5-3)^{2}+(-1+3)^{2}}$

$d=\sqrt{(2)^{2}+(2)^{2}}$

$d_B_C=\sqrt{8}=2.83\ units$

step 4

<em>Find the distance CD</em>

$C(-1, 5), D(2, 4)$

substitute in the formula

$d=\sqrt{(4-5)^{2}+(2+1)^{2}}$

$d=\sqrt{(-1)^{2}+(3)^{2}}$

$d_C_D=\sqrt{10}=3.16\ units$

step 5

<em>Find the distance DE</em>

$D(2, 4),E(2, 1)$

substitute in the formula

$d=\sqrt{(1-4)^{2}+(2-2)^{2}}$

$d=\sqrt{(-3)^{2}+(0)^{2}}$

$d_D_E=\sqrt{9}\ units$

$d_D_E=3\ units$

step 6

<em>Find the distance AE</em>

$A(-2, 1).E(2, 1)$

substitute in the formula

$d=\sqrt{(1-1)^{2}+(2+2)^{2}}$

$d=\sqrt{(0)^{2}+(4)^{2}}$

$d_A_E=\sqrt{16}\ units$

$d_A_E=4\ units$

step 7

Find the perimeter

$P=AB+BC+CD+DE+AE$

substitute the values

$P=2.24+2.83+3.16+3+4=15.23\ units$

Round to the nearest tenth of a unit

$P=15.2\ units$

6 0

2 years ago

What is the example of 897 * 39+(34*964)

Verizon [17]

Answer:

a_n=a_1+(n-1)d

Step-by-step explanation:

sorry for late anwser

4 0

2 years ago

HEEEEELLLPPPP!!! I really need this to be answered im soo confused!!

Marysya12 [62]

Answer:

C

Step-by-step explanation:

∠ AFD = ∠ AFC + ∠ CFD

Given ∠ CFA = 90° and

∠ CFD = 90° - ∠ EFD, that is

∠ CFD = 90° - 62° = 28°, thus

∠ AFD = 90° + 28° = 118° → C

4 0

2 years ago

Read 2 more answers

Charles is planning his son’s birthday party and has a budget of $100. The Go Cart Corral charges $8 per child. How many childre

Montano1993 [528]

<h3>12 children</h3>

because

12 × 8 = 96

hope that helps :)

5 0

3 years ago

The midpoint of \overline{\text{AB}} AB is M(0, -3)M(0,−3). If the coordinates of AA are (2, -5)(2,−5), what are the coordinates

ICE Princess25 [194]

Using the mid-point concept, it is found that the coordinates of B are (-2, -1).

The mid-point of two points is the <u>mean of the coordinates of each point</u>.

In this problem:

The points are: A(2, -5) and B(x,y).

The mid-point is (0, -3).

Applying the concept for both the x and y-coordinates, we have that:

$\frac{x + 2}{2} = 0$

$x + 2 = 0$

$x = -2$

$\frac{-5 + y}{2} = -3$

$-5 + y = -6$

$y = -1$

The coordinates of B are (-2, -1).

To learn more about the mid-point concept, you can take a look at brainly.com/question/10956693

5 0

2 years ago