Answer: C) 163
Step-by-Step Solution:
In the Right Triangle formed to the extreme right, lets mark the angles as
∠1, ∠2 and ∠3.
Therefore, from the Figure :-
∠1 = 73°
∠2 = 90°
By Angle Sum Property :-
∠3 = 180 - (73 + 90)
∠3 = 180 - 163
=> ∠3 = 17°
The Angle which forms a Linear Pair with ∠3 is the Corresponding Angle of ∠r, and Corresponding Angles are Equal.
Therefore,
=> 180 - ∠3
= 180 - 17
=> 163°
Therefore, the Angle that forms the Linear Pair with ∠3 is 163°
This Angle is Corresponding to ∠r and hence they are Equal ie. ∠r = 163°
Hence, ∠r = 163°
Area of parallelogram = bh
3.5 x 2.3
= 8.05cm
Answer:
Step-by-step explanation:
Surface area = lateral area + 2(area of base)
Lateral area = perimeter of base * height.
Because it is a isosceles right triangle, both sides are equal.
= 72
2
= 72. Divide both sides by 2
= 36. Square both sides.
x = 6.
So the perimeter of the base = 6 + 6 +
= 20.485281374239
Lateral area = 20.485281374239 * 7 = 143.397 
Area of base is (1/2)base * height.
(1/2)(6)(6) = 18
Using the surface area formula
surface area = 143.397 + 2(18) = 179.4 
Answer:
CE = 17
Step-by-step explanation:
∵ m∠D = 90
∵ DK ⊥ CE
∴ m∠KDE = m∠KCD⇒Complement angles to angle CDK
In the two Δ KDE and KCD:
∵ m∠KDE = m∠KCD
∵ m∠DKE = m∠CKD
∵ DK is a common side
∴ Δ KDE is similar to ΔKCD
∴ 
∵ DE : CD = 5 : 3
∴ 
∴ KD = 5/3 KC
∵ KE = KC + 8
∵ 
∴ 
∴ 
∴ 
∴ 
∴ KC = (8 × 9) ÷ 16 = 4.5
∴ KE = 8 + 4.5 = 12.5
∴ CE = 12.5 + 4.5 = 17