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raketka [301]
3 years ago
5

Please Help Me!!!!!!!

Mathematics
2 answers:
Svetradugi [14.3K]3 years ago
6 0

Answer:

-3/4

Step-by-step explanation:

Point (-4, 4), and point (0,1)

m = (y2 - y1)/ (x2 - x1) = (4 -1)/(-4-(0)) = 3/(-4) = - 3/4

soldier1979 [14.2K]3 years ago
6 0

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You might be interested in
Evaluate the line integral, where c is the given curve. (x + 9y) dx + x2 dy, c c consists of line segments from (0, 0) to (9, 1)
viktelen [127]
\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=\int_C\langle x+9y,x^2\rangle\cdot\underbrace{\langle\mathrm dx,\mathrm dy\rangle}_{\mathrm d\mathbf r}

The first line segment can be parameterized by \mathbf r_1(t)=\langle0,0\rangle(1-t)+\langle9,1\rangle t=\langle9t,t\rangle with 0\le t\le1. Denote this first segment by C_1. Then

\displaystyle\int_{C_1}\langle x+9y,x^2\rangle\cdot\mathbf dr_1=\int_{t=0}^{t=1}\langle9t+9t,81t^2\rangle\cdot\langle9,1\rangle\,\mathrm dt
=\displaystyle\int_0^1(162t+81t^2)\,\mathrm dt
=108

The second line segment (C_2) can be described by \mathbf r_2(t)=\langle9,1\rangle(1-t)+\langle10,0\rangle t=\langle9+t,1-t\rangle, again with 0\le t\le1. Then

\displaystyle\int_{C_2}\langle x+9y,x^2\rangle\cdot\mathrm d\mathbf r_2=\int_{t=0}^{t=1}\langle9+t+9-9t,(9+t)^2\rangle\cdot\langle1,-1\rangle\,\mathrm dt
=\displaystyle\int_0^1(18-8t-(9+t)^2)\,\mathrm dt
=-\dfrac{229}3

Finally,

\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=108-\dfrac{229}3=\dfrac{95}3
5 0
3 years ago
Answer ASAP
LiRa [457]

Answer:

x = 15°

Step-by-step explanation:

Complementary angles are two angles whose sum = 90°

∠A + ∠B = 90°

3x + 45 = 90

3x = 45

x = 45/3

x = 15°

8 0
2 years ago
Determine a área total e perímetro da figura a seguir:<br><br> Apresente os cálculos.
ra1l [238]

Answer:

Área: 6x2=12, 2x3=6, 10x3=30, 30+6+12=48; <u>área = 48</u>

Perímetro: 10+3+6+2+6+5+2+3+2+3=42; <u>perímetro = 42</u>

6 0
3 years ago
Help me please please
Dimas [21]

Sorry i messed up at first i think it actually is 50.3

Step-by-step explanation:

5 0
2 years ago
What are the solutions (coordinate points) to the system of equations?
Viefleur [7K]

Answer:

x=0,-2

Step-by-step explanation:

Solve the solution by equaling them to each other and solve for x.

x^2+5x+6=3x+6

x^2+5x-3x+6-6=0

x^2+2x=0 (factor out one x)

x(x+2)=0

x has two solutions since there are two options of solving.

1. x=0/(x+2)

  x=0

2. x+2=0/x

   x+2=0

   x=-2

8 0
3 years ago
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