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raketka [301]
3 years ago
5

Please Help Me!!!!!!!

Mathematics
2 answers:
Svetradugi [14.3K]3 years ago
6 0

Answer:

-3/4

Step-by-step explanation:

Point (-4, 4), and point (0,1)

m = (y2 - y1)/ (x2 - x1) = (4 -1)/(-4-(0)) = 3/(-4) = - 3/4

soldier1979 [14.2K]3 years ago
6 0

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My nickname - Lovely

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Find the mean of:<br> 16 32 10 28 8 19 32 26<br> 33 39 98 399
iren2701 [21]

Answer:

91.125

Step-by-step explanation:

Total number/ Total number of quantity

16+32+10+28+8+19+32+26+33+39+98+399

729

Divode by number of quantity (8)

729/8

=91.125

Hope this helps, dont hesitate to Ask in comment below. Mark me as brainliest also appriciated!!

5 0
3 years ago
Find the difference of(ab+8a+1)-(-6ab+4)
vagabundo [1.1K]
Hey there!

When finding the difference of expressions like these, there's a few things you should keep in mind. 

1. When finding the difference of two polynomials, multiply the polynomial that implied to be "negative" by –1 to expand the problem and make it easier to solve. 

2. You combine terms based on their unknown terms, like x, y, x², ab, etc. You cannot combine the terms x and x², but you can combine the terms 6b and 8b by adding them. 

3. You can rearrange your terms however you see fit. If a polynomial is implied as "positive", you can multiply that entire polynomial by +1 to get rid of the parentheses. 

With all that in mind, you can go ahead and solve for your difference, like so:

(ab+8a+1)-(-6ab+4)

(ab+8a+1) (-1(-6ab+4))

(ab+8a+1) + (6ab-4)

ab+6ab+8a+1-4

7ab+8a-3

7ab+8a-3 will be your difference. 

Hope this helped you out! :-)
8 0
3 years ago
In the △ABC, the height AN = 24 in, BN = 18 in, AC = 40 in. Find AB and BC. Consider all possible cases. Case 1 : N∈BC, AB = __,
aivan3 [116]

Answer:

Case 1:

AB = 30

BC = 50

Case 2:

AB = 15.9

BC = 36.7

Case 3: Not possible

Step-by-step explanation:

Given

See attachment for illustration of each case

Required

Find AB and BC

Case 1:

Using Pythagoras theorem in ANB, we have:

AB^2 = AN^2 + BN^2

This gives:

AB^2 = 24^2 + 18^2

AB^2 = 576 + 324

AB^2 = 900

Take square roots of both sides

AB = \sqrt{900

AB = 30

To calculate BC, we consider ANC, where:

AC^2 = AN^2 + NC^2

40^2 = 24^2 + NC^2

1600 = 576 + NC^2

Collect like terms

NC^2 = 1600 - 576

NC^2 = 1024

Take square roots

NC = \sqrt{1024

NC = 32

So:

BC = NC + BN

BC = 32 + 18

BC = 50

Case 2:

Using Pythagoras theorem in ANB, we have:

AN^2 = AB^2 + BN^2

This gives:

24^2 = AB^2 + 18^2

576 = AB^2 + 324

Collect like terms

AB^2 = 576 - 324

AB^2 = 252

Take square roots of both sides

AB = \sqrt{252

AB = 15.9

To calculate BC, we consider ABC, where:

AC^2 = AB^2 + BC^2

40^2 = 252 + BC^2

1600 = 252 + BC^2

Collect like terms

BC^2 = 1600 - 252

BC^2 = 1348

Take square roots

BC = \sqrt{1348

BC = 36.7

Case 3:

This is not possible because in ANC

The hypotenuse AN (24) is less than AC (40)

3 0
3 years ago
ASAP! Guaranteed Brainliest for first decent answer
Gelneren [198K]

Answer:

First differences means take the ordered pairs in increasing order for their x coordinates (assuming the x's go by ones), then subtract each y (except the last) from the y that comes after it.  Keep doing that and you get the first differences.  (The second differences would be what you get if you then subtract each of the first differences from the one that came after it (TMI probably but ...)

Say the points were (1,3), (2,7), (3,11) and (4,15).  The first differences are

7-3 = 4

11-7 = 4

15 - 11 = 4  all 4.  This would also be the slope.  So that is the relationship - they are the same.

6 0
3 years ago
According to the synthetic division below, which of the following statements are true? Check all that apply.
ohaa [14]

Answer:

Correct answer just took the quiz

Step-by-step explanation:

7 0
3 years ago
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