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Delvig [45]
4 years ago
10

a new play premieres on saturday, october 1, and 420 people attend. attendance then decreases by 30% each day. find the attendan

ce on tuesday , october 4
Mathematics
1 answer:
wolverine [178]4 years ago
3 0

Answer:

The attendance on tuesday, october 4, is of 144 people.

Step-by-step explanation:

The attendance after t days is given by the following equation:

A(t) = A(0)(1-r)^{t}

In which A(0) is the attendance on the first day and r is the daily decrease rate.

Premieres on saturday, october 1, and 420 people attend.

This means that A(0) = 420

Attendance then decreases by 30% each day.

This means that r = 0.3

So

A(t) = A(0)(1-r)^{t}

A(t) = 420(1-0.3)^{t}

A(t) = 420(0.7)^{t}

Find the attendance on tuesday , october 4

This is 4-1 = 3 days after saturday. So this is A(3).

A(3) = 420(0.7)^{3} = 144

The attendance on tuesday, october 4, is of 144 people.

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Answer:

D. 251.2 feet

Step-by-step explanation:

On carefully observing the diagram,it can be seen that 80 feet is the diameter of the circular ride, i.e.,the circle,in this case.

The radius of the circle will be half the diameter,r=(80/2) feet=40 feet

The distance of one complete loop of this circular path will be the circumference of the circle.

So, Circumference

=2*π*r

=2*3.14*40 feet

=251.2 feet [ANS]

7 0
3 years ago
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Consider this right triangle.<br> 21<br> 29<br> 20<br> Enter the ratio equivalent to s
AleksAgata [21]

Answer:

Part 1) sin(B)=\frac{21}{29}

Part 2) csc(A)=\frac{29}{20}

Part 3) cot(A)=\frac{21}{20}

Step-by-step explanation:

<u><em>The complete question is</em></u>

Consider this right triangle. 21 29 20 Write the ratio equivalent to: Sin B - CscA- Cot B

The picture of the question in the attached figure

Part 1) Write the ratio equivalent to: Sin B

we know that

In the right triangle ABC

sin(B)=\frac{AC}{AB} ----> by SOH (opposite side divided by the hypotenuse)

substitute the values

sin(B)=\frac{21}{29}

Part 2) Write the ratio equivalent to: Csc A

we know that

In the right triangle ABC

csc(A)=\frac{1}{sin(A)}

sin(A)=\frac{BC}{AB} -----> by SOH (opposite side divided by the hypotenuse)

substitute the values

sin(A)=\frac{20}{29}

therefore

csc(A)=\frac{29}{20}

Part 3) Write the ratio equivalent to: Cot A

we know that

In the right triangle ABC

cot(A)=\frac{1}{tan(A)}

tan(A)=\frac{BC}{AC} -----> by TOA (opposite side divided by the adjacent side)

substitute the values

tan(A)=\frac{20}{21}

therefore

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3 years ago
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OlgaM077 [116]

The missing step in this proof is ∠BAC ≅ ∠BDE ⇒ answer D

Step-by-step explanation:

If two triangles are similar by SAS, then their corresponding angles are

equal and the 3rd corresponding sides have constant ratio

In the two triangles ABC and DBE:

  • ∠ABC ≅ ∠DBE
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Then the two triangles are similar

From similarity:

∠BAC ≅ ∠BDE

∠BCA ≅ ∠BED

∴ The missing step is ∠BAC ≅ ∠BDE

The missing step in this proof is ∠BAC ≅ ∠BDE

Learn more:

You can learn more about triangles in brainly.com/question/3451297

#LearnwithBrainly

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Answer:

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Step-by-step explanation:

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Subtract 8 from both sides: -11=\frac{11}{3}x

Multiply both sides by 3:  -33=11x

Divide both sides by 11:  x=-3

Therefore, point of intersection between both lines is at point (-3, -1)

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Tomtit [17]
It would be $1.20
8.80 + 1.20 = 10
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