1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
leva [86]
2 years ago
12

I WILL GIVE BRAINLIEST

Mathematics
1 answer:
shusha [124]2 years ago
5 0

Answer:

x = -3

Step-by-step explanation:

y\geq -\frac{2}{3} x-3\\
y\leq 3x+8

-\frac{2}{3} x-3=3x+8

Add 2/3 x to both sides:  -3=\frac{11}{3}x+8

Subtract 8 from both sides: -11=\frac{11}{3}x

Multiply both sides by 3:  -33=11x

Divide both sides by 11:  x=-3

Therefore, point of intersection between both lines is at point (-3, -1)

You might be interested in
Plz do number fifteen please!
vodomira [7]
The answer is X=-.75 (the line between -1 and -.5) and Y=-1, I hope this helps!
4 0
3 years ago
“Peaches at the Farmer’s Market cost $2.70 per pound.”
koban [17]

Answer:

non-proportional

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Why does the graph of an exponentai funcation have its shape
Feliz [49]
I need the graph buddy boy
4 0
3 years ago
Find the missing number in this proportion
podryga [215]

Answer:

36

Step-by-step explanation:

Cross multiply

27 x 16 all divided by 12 =36

5 0
3 years ago
A cargo grain leaves Chicago at noon travelling west at 120 km/h. At 2 pm, a passenger train leaves Chicago travelling east at 3
AfilCa [17]

Answer:

a) The trains will be 1520 km apart at 2:40 pm for the cargo train and at 4:40 pm for the passenger train.

b) At that time the cargo train has traveled 560.04 km and the passenger train has traveled 960.12 km.

Step-by-step explanation:

a) First, we need to find the distance traveled by the cargo train in the two hours before the passenger train leaves Chicago:

x_{1} = v_{1}t_{1} = 120 km/h*2h = 240 km                    

Now, we can find the time when the trains will be 1520 km apart:

1520 km = (x_{1} + 240 km) + x_{2}      

Where 1 is for the cargo train and 2 is for the passenger train.

1520 km = (v_{1}*t_{1} + 240 km) + v_{2}t_{2}      

Since we need to calculate the time when the trains are 1520 km apart, t₁ = t₂, so:

1520 km = (v_{1}*t + 240 km) + v_{2}t              

t = \frac{1520 km - 240 km}{120 km/h + 360 km/h} = 2.667h

For the cargo train, it will be 1520 km apart from the passenger train at:

t_{1} = 12 pm + 2 h + 40 min = 2:40 pm

And for a passenger train, it will be 1520 km apart from the cargo train at:

t_{2} = 2 pm + 2 h + 40 min = 4:40 pm  

Hence, the trains will be 1520 km apart at 2:40 pm for the cargo train and at 4:40 pm for the passenger train.  

b) The distance traveled by both trains is given by:

x_{1} = v_{1}*t + 240 km = 120 km/h*2.667 h + 240 km = 560.04 km    

x_{2} = v_{2}*t = 360 km/h*2.667 h = 960.12 km    

Therefore, at that time the cargo train has traveled 560.04 km and the passenger train has traveled 960.12 km.

I hope it helps you!        

5 0
2 years ago
Other questions:
  • What is the 3rd quadrant of 10,20,30,40,50,60​
    5·2 answers
  • Please help with geometry homework!!!
    11·2 answers
  • If TUVW is a parallelogram what is the length of TU
    6·2 answers
  • Over the course of 4 days the price of stock at ACME corporation fell $28. What was the average change in stock price per day?
    13·1 answer
  • PLEASE HELP ITS URGENT
    10·1 answer
  • What is the denominator of the fraction 4/7
    13·2 answers
  • Find the value of the variables leave answer in simplest radical form
    12·2 answers
  • Help with c pls!! I Pretty difficult for me
    10·2 answers
  • Solve this system of equations. <br> x-y=2 <br> 2.5x + y =5
    12·1 answer
  • What are the center and radius of the circle defined by the equation x^2 + y^2 -6x + 4y + 4=0
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!