Answer: There are many different types of application architectures, but the most prominent today, based on the relationships between the services are: monoliths and N-tier architecture, microservices, and event-driven architecture and service-oriented architecture.
Explanation: A layered or N-tier architecture is a traditional architecture often used to build on-premise and enterprise apps, and is frequently associated with legacy apps.
A monolith, another architecture type associated with legacy systems, is a single application stack that contains all functionality within that 1 application. This is tightly coupled, both in the interaction between the services and how they are developed and delivered.
Microservices are both an architecture and an approach to writing software. With microservices, apps are broken down into their smallest components, independent from each other. Each of these components, or processes, is a microservice.
With an event-driven system, the capture, communication, processing, and persistence of events are the core structure of the solution. This differs from a traditional request-driven model.
The service-oriented architecture (SOA) is a well-established style of software design, that is similar to the microservices architecture style.
Answer:
D
Explanation:
The answer is D because if you're looking for lightweight materials, you'll be dealing with chemistry, and chemistry is sience.
Answer:
age=int(input("Enter age"))
if age>=18:
print("You are Young")
else
print("You are child")
Explanation:
if you have any query or any problem kindly ask in comment
Answer:
Identify the purpose, audience, and audience needs for preparing image,Identify three phases that might appear in a project plan. When planning your design project you might include on an outline the goals.
Answer:
Explanation:
a)use order by clause for sorting
for $x in doc("books.xml")/bib/book order by xs:float($x/price) return $x/title (default sorted in ascending order)
or
for $x in doc("books.xml")/bib/book order by xs:float($b/price) descending return $b/title (sorted in descending order)
b)doc("books.xml")//book[author = 'Abiteboul']
c)for $x in distinct-values(doc("bib.xml")/bib/book/author)
return <res>
<name>{$x}</name>
<count>
{count (doc("bib.xml")//book[exists(indexof(author,$x))]) }
</count>
<res>
