Question

Isaac throws an apple straight up (in the positive direction) from 1.0m above the ground, reaching a maximum height of 35 meters. Neglecting air resistance, what is the ball's velocity when it hits the ground?

Answer 1

Consider that when heigt is 35 meters, the velocity is zero. The you can use the formula for free fall with initial velocity zero

Vf = √(2gh) = √(2*9.8m/s^2 * 35m) = √686m^2/s^2 = 26.2 m/s

Assumption: 35 m is the maximum height from the ground, else, if the maximum heigth from the ground is 35 m + 1 m = 36 m, the numbers are:

Vf = √(2*9.8m/s^2*36m) = 26.6 m/s

Answer 2

Ht  = 1 + vt - 16t^2

1 + v(v/32) - 16 (v/32)^2 = 35

v = 8 Root 34


ht = 1 + 8root34 t - 16t ^2
h = o
t = 2.94

vt = 8 root34 - 32t
v = 8 root 34  - 32(2.94)
=  - 47.43 ft/s

hope this helps