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Marina86 [1]
3 years ago
15

Help ASAP thanks !!!

Physics
1 answer:
Ann [662]3 years ago
3 0

Answer:

true

Explanation:

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A coil consists of 200 turns of wire. Each turn is a square of side d = 18 cm, and a uniform magnetic field directed perpendicul
vampirchik [111]

Answer:

Induced emf in the coil, \epsilon=4.05\ volts

Explanation:

Given that.

Number of turns in the coil, N = 200

Side of square, d = 18 cm = 0.18 m

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To find,

The magnitude of the induced emf in the coil while the field is changing.

Solution,

We know that due to change in the magnetic field, an emf gets induced in the coil. The formula of induced emf is given by :

\epsilon=\dfrac{d\phi}{dt}

\phi = magnetic flux

\epsilon=-\dfrac{d(NBA)}{dt}

A is the ares of square

\epsilon=AN\dfrac{d(B)}{dt}

\epsilon=AN\dfrac{B_f-B_i}{t}

\epsilon=(0.18)^2\times 200 \times \dfrac{0.5-0}{0.8}

\epsilon=4.05\ volts

So, the induced emf in the coil is 4.05 volts. Hence, this is the required solution.

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