Help ASAP thanks !!!

Consider a field of insects, all of which have essentially the same mass.

Over [174]

If the total momentum of the insects is zero, this means all of the insects are at rest or are moving in opposite of each other. Same if the total kinetic energy is zero.

<h3>What is momentum? </h3>

Momentum is the quantity of motion which is multiplied by the amount of matter moved i.e., mass and the velocity at which it moves. Because, the object is in motion, it is a vector quantity, it has both direction and magnitude. It is determined by the product of the object's mass and the velocity of object.

If the total momentum of the insects is zero, this could mean anything of the two things. Either, all of the insects are at rest or an equal amount of insects are moving in opposite direction of each other which cancels out the total momentum of the insects.

If the total kinetic energy of the insects is zero, this means either all of the insects are at rest or an equal amount of insects are moving in opposite direction of one another which results into canceling out the energy.

Learn more about Motion here:

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7 0

2 years ago

The center of a moon of mass m is a distance D from the center of a planet of mass M. At some distance x from the center of the

nataly862011 [7]

Answer with Explanation:

Let rest mass $m_0$ at point P at distance x from center of the planet, along a line connecting the centers of planet and the moon.

Mass of moon=m

Distance between the center of moon and center of planet=D

Mass of planet=M

We are given that net force on an object will be zero

a.We have to derive an expression for x in terms of m, M and D.

We know that gravitational force= $\frac{GmM}{r^2}$

Distance of P from moon=D-x

$F_m$ =Force applied on rest mass due to m

$F_m$ =Force on rest mass due to mas M

$F_M=F_m$ because net force is equal to 0.

$F_m=F_M$

$\frac{Gm_0m}{(D-x)^2}=\frac{Gm_0M}{x^2}$

$\frac{m}{(D-x)^2}=\frac{M}{x^2}$

$\frac{x^2}{(D-x)^2}=\frac{M}{m}$

$\frac{x}{D-x}=\sqrt{\frac{M}{m}}$

Let $R=\sqrt{\frac{M}{m}}$

Then, $\frac{x}{D-x}=R$

$x=DR-xR$

$x+xR=DR$

$x(1+R)=DR$

$x=\frac{DR}{1+R}$

b.We have to find the ratio R of the mass of the mass of the planet to the mass of the moon when x= $\frac{2}{3}D$

Net force is zero

$F_m=F_M$

$\frac{Gm_0m}{(D-\frac{2}{3}D)^2}=\frac{Gm_0M}{\frac{4}{9}D^2}$

$\frac{m}{\frac{D^2}{9}}=\frac{9M}{4D^2}$

$\frac{M}{m}=4$

Hence, the ratio R of the mass of the planet to the mass of the moon=4:1

8 0

4 years ago

A student is told to use 20.0 g of sodium chloride to make an aqueous solution that has a concentration of 10.0 g/L (grams of so

Stells [14]

Answer:

she should add solute to the solvent

Explanation:

Given data :

Mass of the sodium chloride, = 20.0 g

Concentration of the solution = 10 g/L

Volume of 20.0 g of sodium chloride = 7.50 mL

Now, from the concentration, we can conclude that for 10 g of sodium chloride volume of the solution is 1 L

thus, for 20 g of sodium chloride volume of the solution is 2 L or 2000 mL

also,

Volume of solution = Volume of solute(sodium chloride) + volume of solvent (water)

thus,

2000 mL = 7.5 mL + volume of solvent (water)

or

volume of water = (2000 - 7.5) mL

or

volume of water = 1992.5 mL

or

volume of water = 199.25 L ≈ 199 L

6 0

3 years ago

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Glenn shoots an arrow at a 30.0 degree angle. It has a velocity of 65.0 m/s How far will the arrow travel?

Burka [1]

I just shot my shot at this little 52 ms far

3 0

3 years ago

If you take rocks from the Earth to the moon (5 points)

Lemur [1.5K]

the mass would remain the same and the weight would change. mass defines the actual amount of an object, while weight is the force gravity has on that object. gravity is different on the moon and the earth therefore the weight will change

8 0

3 years ago

Read 2 more answers