Which statement places events during the Space Race in the correct order from the earliest to the most recent?

A 6.0-kilogram cart initially traveling at 4.0 meters per second east accelerates uniformly at 0.50 meter per second squared eas

VMariaS [17]

Answer: 5.5m/s

Explanation:

vf=vi+at

vf= 4.0m/s + (0.50m/s^2)(3.0s)

3 0

3 years ago

A 2 kg car accelerated from 10 m's to 20 m/s using a force of 3000N. How quickly did it

elena-14-01-66 [18.8K]

Answer:

the car accelerates in

$\frac{1}{150} \: or \: 0.006 \: second$

Explanation:

here's the solution : -

we know,

=》

$force = mass \times acceleration$

=》

$acceleration = \frac{force}{mass}$

=》

$a = \frac{3000}{2}$

=》

$a = 1500$

so, acceleration = 1500 m/s^2

now,

=》

$a = \frac{v - u}{t}$

here, a = acceleration, v = final velocity,

u = initial velocity, t = time taken.

So,

=》

$1500 = \frac{20 - 10}{t}$

=》

$1500 = \frac{10}{t}$

=》

$t = \frac{10}{1500}$

=》

$t = 0.006 \: sec$

7 0

3 years ago

Earth’s crust continuously melts and solidifies in the upper mantle. Why does oceanic crust solidify faster than continental cru

Softa [21]

The oceanic crust solidifies faster than the continental crust. Because when magma comes into contact with ocean water it cools faster than when it reaches continental rock. Option C is correct.

<h3>What is the crust?</h3>

The outermost layer of a terrestrial planet is referred to as its "crust."

In the upper mantle, the Earth's crust is constantly melting and solidifying. Compared to magma beneath the continental crust, the oceanic crust has a lower temperature.

Magma cools more quickly when it comes into touch with ocean water than when it hits continental rock. causes the continental crust to solidify more slowly than the oceanic crust.

Hence option C is correct.

To learn more about the crust refer;

brainly.com/question/13428623

#SPJ1

3 0

2 years ago

One of the most important properties of materials in many applications is strength. Two of the qualitative measures of the stren

katrin2010 [14]

To solve this exercise it is necessary to take into account the concepts related to Tensile Strength and Shear Strenght.

In Materials Mechanics, generally the bodies under certain loads are subject to both Tensile and shear strenghts.

By definition we know that the tensile strength is defined as

$\sigma = \frac{F}{A}$

Where,

$\sigma =$ Tensile strength

F = Tensile Force

A = Cross-sectional Area

In the other hand we have that the shear strength is defined as

$\sigma_y = \frac{F_y}{A}$

where,

$\sigma_y =$ Shear strength

$F_y =$ Shear Force

$A_0 =$ Parallel Area

PART A) Replacing with our values in the equation of tensile strenght, then

$311*10^6 = \frac{F}{(15*10^{-6})(30*10^{-2})}$

Resolving for F,

$F= 1399.5N$

PART B) We need here to apply the shear strength equation, then

$\sigma_y = \frac{F_y}{A}$

$210*10^6 = \frac{F_y}{15*10^{-6}30*10^{-2}}$

$F_y = 945N$

In such a way that the material is more resistant to tensile strength than shear force.

6 0

4 years ago

n this experiment, you will measure mass and volume of various sport balls, both regularly shaped ball and irregularly shaped. W

pentagon [3]

Explanation :

Density of an object can determine using mass and volume. We can measure mass and volume of various sports ball, both regular shaped ball and irregular shaped ball.

Density for regularly shaped ball and that of irregularly shaped ball is different.

Suppose that mass of an object is 100g and the volume is $2000\ cm^3$ . So, using this data we can find density of that object as

$density=\frac{mass}{volume}$

$\rho =\frac{100}{2000}$

$\rho =0.05\ g/cm^3$

5 0

4 years ago

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