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3 years ago

20 POINTS- ANSWER IF YOU KNOW

Mathematics

2 answers:

Liula [17]3 years ago

7 0

Answer: It will hold 9,000 gallons (I'm guessing as that is the stand unit of water for something like this)

Step-by-step explanation:

60 * 25 = 1,500

1500 * 6 = 9000

IRISSAK [1]3 years ago

6 0

Answer:

9000 feet cubed

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What is the distance between points (12, 4) and (12, -10) on the coordinate plane

saul85 [17]

The distance is 14 between coordinates'

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3 years ago

Which angles are supplementary angles?

7nadin3 [17]

Answer:

KJM and KJH

Step-by-step explanation:

Supplementary angles are angles that equal 180 degrees

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3 years ago

Read 2 more answers

I WILL AWARD BRAINLIEST!! PLEASE HELP!!! The figure below shows the movement of a pedestrian from point B to point E. Using the

jeyben [28]

Answer:

Step-by-step explanation:

A) What is the speed of the pedestrian BC, CD, and DE?

Speed from B to C = distance/time = (40 - 20) / 4 = 20/4

= 5 km/h

Speed from C to D = distance/time = 0 / 2

= 0 km/h

Speed from D to E = distance/time = (20 - 0) / (10 - 6) = 20/4

= 5 km/h

B) After what time since the stop did he arrive at point E?

Since the stop at D, he arrived at E after (10 - 6) = 4 h

C) Write the formulas for function d(t) for sections BC, CD, and DE

For BC, d = 40 when t = 0 and d = 20 when t = 4

So d(t) = 40 - 5t

For CD, d = 20 when t = 4 and t = 6

So d(t) = 20

For DE, d = 20 when t = 6 and d = 0 when t = 10

So d(t) = 5 * (10 - t) or d(t) = 50 - 5t

4 0

3 years ago

Read 2 more answers

The measure of ∠AKG is 133°.

denis23 [38]

Mes ∠AKG = mes ∠AKD + mes ∠ DKG

133° = mes ∠ AKD + 87°

133° - 87° = mes ∠AKD

∠AKD = 46°

7 0

3 years ago

When an object is droppednbsp on a certain earth dash like planet comma on a certain earth-like planet, the distance it falls in

ANTONII [103]

Answer:

(a) $s(44) = 3.52*10^{6}ft$

(b) $v(44) = 10*x^{5} ft/s$

Step-by-step explanation:

$s(t) = 1818t^{2}$

(a) when t = 44sec

$s(44) = 1818(44^{2}) = 1818(1936)\\ \\s(44) = 3519648ft$

s(44) ≅ $3520000=3.52*10^{6}ft$

(b) How fast the hammer is traveling i.e. the speed of the hammer.

To find speed, we differentiate the distance s(t) with respect to time, t

$speed,v=\frac{ds(t)}{dt}=\frac{d}{dt}(1818t^{2}) \\\\v = 1818*2t^{2-1}= 1818*2t\\ \\v = 3636t$

at t = 44sec,

$v = 3636*44=159984ft/s$

$v$ ≅ $160000ft/s = 1.6*10^{5}ft/s$

(c) The hammer's acceleration can be obtained by differentiating the speed v(t) with respect to time, t

$acceleration, a = \frac{dv}{dt}=\frac{d}{dt}(3636t)\\ \\a = 3636*1= 3636\\\\a = 3636ft/s^{2}$

There's no need to substitute t = 44sec because the acceleration is independent of time.

3 0

3 years ago