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Flauer [41]
3 years ago
14

Help ASAP please! JKL is a right triangle. JL = 10, KL = 8, and JK = 6. What is cos L?

Mathematics
2 answers:
dalvyx [7]3 years ago
7 0

Answer:

Answer B is correct

Step-by-step explanation:

Hey there,

cos \; L \;\;= \frac{adjecent}{hypotenuse}

cos\; L  = \frac{8}{10}

The answer is,

\frac{8}{10}

Hope this helps you.

Let me know if you have any other questions :-)

Alisiya [41]3 years ago
3 0

Answer:

cos l = 8/10

Step-by-step explanation:

cos = b/h

=> cos l = 8/10

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She is expected to pay $4508 up front.

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3 years ago
Calculus Question, just the first line. Other stuff is just my work...
aleksandr82 [10.1K]
What are you even asking us
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4 years ago
Andrea, Justin, and Virginia went to an office supply store. Andrea bought 6 pencils, 7 markers, and 8 erasers. Her total was $1
olga2289 [7]

Answer:

x=0.25\,,\,y=1.75\,,\,z=0.25

Step-by-step explanation:

Let x,y,z denotes number of pencils, markers, erasers respectively.

For Andrea:

6x+7y+8z=15.75\,\,\,(i)

For Justin:

6x+8y+5z=16.75\,\,\,(ii)

For Virginia:

5x+5y+7z=11.75\,\,\,(iii)

On subtracting equations (i) and (ii), we get

(6x+7y+8z)-(6x+8y+5z)=15.75-16.75\\-y+3z=-1\\y-3z=1\\y=1+3z

Put y=1+3z in equation (i)

6x+7(1+3z)+8z=15.75\\6x+29z=8.75\,\,\,(iv)

Put y=1+3z in equation (iii)

5x+5(1+3z)+7z=11.75\\5x+22z=6.75\,\,\,(v)

Multiply equation (iv) by 5 and equation (v) by 6 and then subtract both the equations.

5(6x+29z)-6(5x+22z)=5(8.75)-6(6.75)\\13z=3.25\\z=\frac{3.25}{13}=0.25

Put z=0.25 in equation y=1+3z

y=1+3(0.25)=1.75

Put y=1.75\,,\,z=0.25 in equation (i)

6x+7(1.75)+8(0.25)=15.75\\6x+12.25+2=15.75\\6x=1.5\\x=0.25

8 0
4 years ago
Answer in factored form 13+14m+m^2
natta225 [31]
<span>Solution


m = {-13, -1}</span>
5 0
4 years ago
Read 2 more answers
Helpppp pleaseee i need a quick answer
aleksandr82 [10.1K]

Answer:

32 i think

Step-by-step explanation:

its 16 cm, so 2 full rotations would be 16 times 2

which is 32

4 0
3 years ago
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