Question

Help ASAP please! JKL is a right triangle. JL = 10, KL = 8, and JK = 6. What is cos L?

Answer 1

Answer:

Answer B is correct

Step-by-step explanation:

Hey there,

$cos \; L \;\;= \frac{adjecent}{hypotenuse}$

$cos\; L = \frac{8}{10}$

The answer is,

$\frac{8}{10}$

Hope this helps you.

Let me know if you have any other questions :-)

Answer 2

Answer:

cos l = 8/10

Step-by-step explanation:

cos = b/h

=> cos l = 8/10